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Question
9x²-12x+3 , factorise
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Solution
(i) 9x2–12x+3=3(3x2–4x+1) [taking 3 common factor]
=3(3x2–3x–x+1) [By spitting the middle term]
=3[3x(x−1)–1(x–1)
[Took 3x common from first term and -1 common from second term]=
3(3x−1)(x–1)]
[Took (x-1) common]
=3(3x2–3x–x+1) [By spitting the middle term]
=3[3x(x−1)–1(x–1)
[Took 3x common from first term and -1 common from second term]=
3(3x−1)(x–1)]
[Took (x-1) common]
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