KCL and KVL
Trending Questions
Q. Two incadesecent light bulbs of 40W and 60 W rating are connected in series across the mains Then
- the bulb together consume 100W
- the bulb together consume 50 W
- the 60 W bulb glows brighter
- the 40 W bulb glows brighter
Q. In the circuit shown in the figure, the value of the current i will be given by
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1134909/original_dia_25_que.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1134909/original_dia_25_que.png)
- 0.31 A
- 1.25 A
- 1.75 A
- 2.5 A
Q.
For the combination of resistors shown in the following figure, find the equivalent resistance between and
Q. A 3 V dc supply with an internal resistance of 2Ω supplies a passive non- linear resistance characterized by the relation VNL=I2NL. The power dissipated in the non linear resistance is
- 1.0 W
- 1.5 W
- 2.5 W
- 3.0 W
Q. In figure, the value of the source voltage is
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1134527/original_diagram_que_18_que.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1134527/original_diagram_que_18_que.png)
- 12V
- 24V
- 30V
- 44 V
Q. A segment of a circuit is shown in figure VR=5V, Vc=4 sin2t. The voltage VL is given by
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151404/original_diagram_15_corrected.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151404/original_diagram_15_corrected.png)
- 3 - 8 cos 2t
- 32 sin 2t
- 16 sin 2t
- 16 cos 2t
Q. The equivalent capacitance of the input loop of the circuit shown is
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151513/original_diagram_28_que_corrected.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151513/original_diagram_28_que_corrected.png)
- 2μF
- 100μF
- 200μF
- 4μF
Q. In the circuit shown in figure, X is an element which always absorbs power. During a particular operation, it sets up a current to 1 amp in the direction shown and absorbs a power Px, It is possible that X can absorb the same power Px for another current i. Then the value of this current is
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151260/original_diagram_3_corrected.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151260/original_diagram_3_corrected.png)
- (3 - √14) A
- (3 + √14) A
- 5 A
- None of these
Q. If the 12 Ω resistor draws a current of 1 A as shown in the figure, the value of resistance R is
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151529/original_diagram_32_que_corrected.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151529/original_diagram_32_que_corrected.png)
- 4 Ω
- 6 Ω
- 8 Ω
- 18 Ω
Q. Find VAB?
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1387333/original_3.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1387333/original_3.png)
- 15 V
- - 30 V
- + 30 V
- - 15 V
Q. Find the value of Io (in A) from the below given circuit.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1329139/original_task_3.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1329139/original_task_3.png)
- 30
Q. Find the value of Vx (in V) from the network shown below.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1329129/original_task_4.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1329129/original_task_4.png)
- 9
Q. In the figure, the value of resistor R is (25+12)Ω, where I is the current in amperes. The current I is___.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151780/original_dia_39_que_corrected.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1151780/original_dia_39_que_corrected.png)
- 10
Q. Find Ix ?
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1387345/original_4.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1387345/original_4.png)
- -8A
- +8A
- -4A
- +4A
Q. An AC voltage source V = 10 sin(t) volts is applied to the following network. Assume that R1 = 3 kΩ, R2 = 6 kΩ, and R3 = 9 kΩ, and that the diode is ideal.
RMS current Irms (in mA) through the diode is ___
____.
RMS current Irms (in mA) through the diode is ___
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1147219/original_54.png)
- 1
- 2
- 6
- 7
Q. The current i4 in the circuit of figure is equal to
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1145309/original_7.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1145309/original_7.png)
- 12 A
- -12 A
- 4 A
- None of these