Nortons theorem (NT)

Q. Norton's theorem states that a complex network connected to a load can be replaced with an equivalent impendance

1. In series with a current source
2. In parallel with a voltage source
3. In series with a voltage source
4. In parallel with a current source

Q. Consider the circuit shown in the figure below;
The Norton's equivalent seen across the terminal A and B is

1. $I_N=0,R_N=100\Omega$
2. $I_N=3.67A,R_N=24\Omega$
3. $I_N=8.8A,R_N=24\Omega$
4. $I_N=1.6A,R_N=100\Omega$

Q. For the circuit shown in figure. The Norton equivalent source current value is_____A and its resistance is_____ Ohms.

1. $4.5A,2\Omega$
2. $3A,4.5\Omega$
3. $2A,4.5\Omega$
4. $2A,2\Omega$

Q. The value of current flowing though the $50\Omega$ resistor in the bridge network shown in figure is________A.

1. 0.55
2. 0.21
3. 0.95
4. 0.76

Q.

Can you use superposition with dependent sources?

Q.

The Norton's equivalent source in amperes as seen into the terminals X and Y is

1. 1

Q. In the network shown below, remove terminal C and obtain the Norton equivalent seen at terminals a and b.

1. -0.3 A parallel with 6.67 $\Omega$
2. -0.21 A in parallel with 0.67 $\Omega$
3. 0.4 A parallel with 3.4 $\Omega$
4. 0.42 A parallel with 6.67 $\Omega$

Q. What is the magnitude of $V_0$, when power loss in 10 $\Omega$ resistor is 90 watt?

1. 15 V
2. 9 V
3. 6 V
4. 3 V