Impulse response of Second Order System
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Q. A control system with certain excitatioin is governed by the following mathematical equation
d2xdt2+12 dxdt+118x=10+5e−4t+2e−5t
The natural time constants of the response of the system are
d2xdt2+12 dxdt+118x=10+5e−4t+2e−5t
The natural time constants of the response of the system are
- 2s and 5s
- 3s and 6s
- 4s and 5s
- 1/3s and 1/6s
Q. A second-order real system has the following properties:
(a) The damping ratio ξ=0.5 and undamped natural frequency ωn=10rad/s.
(b) The steady state value of the output to a unit step input is 1.02.
The transfer function of the system is
(a) The damping ratio ξ=0.5 and undamped natural frequency ωn=10rad/s.
(b) The steady state value of the output to a unit step input is 1.02.
The transfer function of the system is
- 102s2+5s+100
- 102s2+10s+100
- 102s2+s+100
- 102s2+5s+100
Q. A linear, time - invarient, casual continuous time system has a rational transfer function with simple poles at s=−2 and s=−4, and one simple zero at s=−1.A unit step u(t) is applied at the input of the system. At steady state, the output has constant value of 1. The impulse response of this system is
- [e−2t+e−4t]u(t)
- [−4e−2t+12e−4t−e−t]u(t)
- [−4e−2t+12e−4t]u(t)
- [−0.5e−2t+1.5e−4t]u(t)
Q. The differential equation 100d2ydt2−20dydt+y=x(t) describes a system with an input x(t) and an output y(t).The system, which is initially relaxed is excited by a unit step input. The output y(t) can be represented by the waveform
Q. Given figure shows a closed loop unity feedback system. The controller block has transfer function denoted by Gc(s). The controller is cacaded to plant, which is denoted by Gp(s)
The loop transfer function Gc(s) is
The loop transfer function Gc(s) is
- 1+0.1ss
- −1+0.1ss
- −ss+1
- ss+1
Q. For a second order closed-loop system shown in the figure, the natural frequency (in rad/s) is
- 16
- 4
- 2
- 1
Q. Match the unit-step responses(1), (2) and (3) with transfer functions P(s), Q(s) and R(s), given below.
P(s)=−1(s+1);Q(s)=2(s−1)(s+10)(s+2);R(s)=1(s+1)2
P(s)=−1(s+1);Q(s)=2(s−1)(s+10)(s+2);R(s)=1(s+1)2
- P(s)−(3), Q(s)−(2), R(s)−(1)
- P(s)−(1), Q(s)−(2), R(s)−(3)
- P(s)−(2), Q(s)−(1), R(s)−(3)
- P(s)−(1), Q(s)−(3), R(s)−(2)