Newton's Interpolation

Q. The value of a function f(x) are tabulated below

x	0	1	2	3
f(x)	1	2	1	10

Using Newton's forward difference formula, the cubic polynomial that can be fitted to the above data, is

1. $2x^3+7x^2-6x+2$
2. $2x^3-7x^2+6x-2$
3. $x^3-7x^2-6x+1$
4. $2x^3-7x^2+6x+1$