Exponential Distribution
Trending Questions
Q. Let X1 and X2 be two independent exponentially distributed random variables with means 0.5 and 0.25, respectively. Then Y=min(X1, X2) is
- exponentially distributed with mean 1/6
- exponentially distributed with mean 2
- normally distributed with mean 3/4
- normally distributed with mean 1/6
Q.
Let Z be an exponential random variable with mean 1. That is, the cumulative distribution function of Z is given by
Fz(x)=(1−e−xifx≥00ifx<0
Then Pr(Z > 2 | Z > 1), rounded off to two decimal places, is equal to
- 0.367
Q. The number of parameters in the univariate exponential and Gaussian distributions, respectively are
- 2 and 2
- 1 and 2
- 2 and 1
- 1 and 1