Methods
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Q.
Find and correct the errors in the mathematical statement
Q. A numerical solution of the equation can be obtained using Newton- Raphson method
f(x)=2√x+3x−6=0
If the starting value is x = 3 for the first iteration, the value of x that is to be used in the next step is
f(x)=2√x+3x−6=0
If the starting value is x = 3 for the first iteration, the value of x that is to be used in the next step is
- 0.298
- 2.385
- 1.192
- 0.596
Q. Solve the equation x=e−x using Newton-Raphson method. Starting with an initial guess values x0=0, the value of x after first iteration is .
- -0.050
- -1
- 0.50
- 1
Q. Only one of the real roots of f(x)=x6−x−1 lies in the interval 1≤x≤2 and bisection method is used to find its value. For achieving an accurancy of 0.001, the required minimum number of iteration is
- 10
Q. Starting from x0=1, one step of Newton-Raphson method in solving the equation 2x3+5x−8=0 gives the next value (x1) as
- 56
- 1112
- 63
- 1211
Q. The Newton-Raphson method formula for finding the square root of a real number N from the equation x2−N=0 is
- xi+1=5xi2
- xi+1=3xi2
- xi+1=12(xi+Nx2i)
- xi+1=12(xi+Nxi)