Pipe Network
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- C=√(g8f)
- C= ⎷⎛⎜ ⎜ ⎜ ⎜⎝8gf14⎞⎟ ⎟ ⎟ ⎟⎠
- C=√(8gf)
- C=√(f8g)
A pipe of 0.7 m diameter has a length of 6 km and connects two reservoirs A and B. The water level in reservoir A is at an elevation 30 m above the water level in reservoir B. Halfway along the pipe line, there is a branch through which water can be supplied to a third reservoir C. The friction factor of the pipe is 0.024. the quantity of water discharged into reservoir C is 0.15 m3/s. Considering the acceleration due to gravity as 9.81 m/s2 and neglecting minor losses, the discharge (in m3/s) into the reservoir B is
- 0.572
- Continuity principle demands that flow into a network junction is equal to the flow out of it.
- Momentum equation must be satisfied so that the force in each loop is balanced.
- Darcy-Weisbach head loss equation is to be used in computing head loss in elementary circuits. The equation is of the form hL=KQn.
- ∑hL=∑kQn must be equated to zero. If not, a flow correction factor △Q is to be made for arriving at a solution.
A pipe network consists of a pipe of 60 cm diameter and branches out at a point T into two branches, one of 30 cm diameter and the other of 45 cm diameter. These branch pipes rejoin at a point B. The velocity in the first branch (of 45 cm diameter) is 1.5 m/sec. Which one of the following statements is true?
- The velocity in the second branch is 1.0 m/sec.
- The velocity in the second branch is 2.25 m/sec.
- The velocity in the second branch is 23=0.667 m/sec.
- The potential drop between T and B in both branches is the same.
- The algebraic sum of discharges around each elementary circuit must be zero
- The head at each node must be the same
- The algebraic sum of the drop in piezometric head around each elementary circuit is zero
- The piezometric head loss in each line of each circuit is the same
A triangular pipe network is shown in the figure
The head loss in each pipe is given by hf =r.Q1.8 with the variables expressed in a consistent set of units. The value of r for the pipe AB is 1 and for the pipe BC is 2. If the discharge supplied at the point A (i.e., 100) is equally divided between the pipes AB and AC, the value of r (up to 2 decimal places) for the pipe AC should be
- 0.62
- 3
- 4
- 5
- 6
- 1
Discharges Q1, Q2 and Q3 are related as
- Q1+Q2=Q3
- Q1=Q2+Q3
- Q2=Q1+Q3
- Q1+Q2+Q3=0
- Q1=Q3
- Q2=Q1+Q3
- hf1=hf3
- hf1=hf2=hf3
- 1 and 3
- 2 and 3
- 1 and 4
- 2 and 4
- 104 lps
- 134 lps
- 165 lps
- 196 lps
[Note: Re is Reynolds number,
f = friction coefficient,
εD=relative roughness
V = velocity]
- assume f, compute: V, Re, εD and calculate f; and repeat if necessary
- assume Re, compute f, check εD
- assume V, compute Re and calculate f, V again
- assume ε compute V, Re, and calculate f