Extrusion Pressure and Extrusion Load
Trending Questions
Q. A brass billet is to be extruded from its initial diameter of 100mm to a final diameter of 50 mm. The working temperature of 700∘C and the extrusion constant is 250 MPa. The force required for extrusion is
- 5.44 MN
- 2.72 MN
- 1.36 MN
- 0.36 MN
Q. Using direct extrusion process, a round billet of 100 mm length and 50 mm diameter is extruded Considering an ideal deformation process (no friction and no redundant work) extrusion ratio 4 and average flow stress of material 300 MPa, the pressure (MPa) on the ram will be
- 416
- 624
- 700
- 832
Q. A round billet made of brass is to be extruded (extrusion constant = 250 MPa) at 700∘C. The billet diameter is 100 mm and the diameter of the extrusion is 50 mm. The extrusion force required (in MN) is
- 1.932
- 2.722
- 3.423
- 4.650
Q. A stainless steel cans of inner diameter 67 mm, thickness 3.5 mm, base thickness 5.71 mm and height 121 mm (excluding the base thickness) will be manufactured using an extrusion process. Billets used for the process have a diameter of 67 mm. The friction coefficient at the punch work piece is 0.03 and the workpiece die interface is 0.05. Assume the flow properties of the material are given as extrusion constant K=450 MPa, n = 0.16. The extrusion force is given by
- 4857
Q. A copper billet of diameter 100 mm is to be extruded by an extrusion load of 2.72 MN. If the extrusion constant is 250 MPa. Then, the final diameter of the billet after final extrusion is
- 40.03 mm
- 50.03 mm
- 38.05 mm
- 42.53 mm
Q. A round billet of brass is to be extruded (Extrusion constant = 250 MPa) at 800oC. The billet diameter is 100 mm and the extruded component diameter is 50 mm. Then the extrusion force required is
- 2.5 MN
- 6.1 MN
- 10.7 MN
- 2.7 MN