Force and Work done in Punching and Blanking
Trending Questions
Q. 10 mm diameter holes are to be punched in a steel sheet of 3 mm thickness. Shear strength of the material is 400 N/mm2 and penetration is 40%. Shear provided on the punch is 2 mm. The blanking force during the operation will be
- 22.6 kN
- 37.7 kN
- 61.6 kN
- 94.3 kN
Q. Determine the load required to punch a 20mm diameter hole in a 2mm thick sheet. The properties of the material of the sheet are:
Tensile strength −580MPa
Yield strength in tension −410MPa
Shear strength −350MPa
Yield strength in shear −250MPa
The load is kN is
Tensile strength −580MPa
Yield strength in tension −410MPa
Shear strength −350MPa
Yield strength in shear −250MPa
The load is kN is
- 31.40
- 43.98
- 64.40
- 91.10
Q. The shear strength of a sheet metal is 300 MPa. The blanking force required to produce a blank of 100 mm diameter from a 1.5 mm thick sheet is close to
- 45 kN
- 70 kN
- 141 kN
- 3500 kN
Q. Circular blanks of 10 mm diameter are punched from an aluminium sheet of 2 mm thickness. The shear strength of aluminum is 80 MPa. The minimum punching force required in kN is
- 2.57
- 3.29
- 5.03
- 6.33
Q. A hole of 50 mm diameter is to be punched on a 2 mm thick sheet. The shear stress for the material can be taken as 3.1 kN/mm2. Assuming gradual variation of load with punch travel and penetration to thickness ratio = 0.5, the energy required to punch the hole is
- 973.89 J
- 1216.21 J
- 1947.78 J
- 2609.76 J
Q. A rectangular hole of size 100 mm timses 50 mm is to be made on a 5 mm thick sheet of steel having ultimate tensile strength and shear strength of 500 Mpa and 300 MPa, respectively. The hole is made by a punching process. Neglecting the effect of clearance, the punching force (in kN) is
- 300
- 450
- 600
- 750
Q. A ϕ25mm hole is pierced in a t=2.5mm thick steel sheet having shear strength τ=350MPa. If the diametral clearance is given by the expression c=0.0064√τ, the die diameter (in mm), punch diameter (in mm) and punch force in (kN) respectively are
- 25.0, 25.3, 171.8
- 25.0, 24.7, 68.75
- 24.7, 25.0, 171.8
- 25.3, 25.0, 68.75
Q. For 50% penetration of work material, a punch with single shear equal to thickness will
- reduce the punch load to half the value
- increase the punch load by half the value
- maintain the same punch load
- reduce the punch load to quarter load
Q. In a blanking operation to produce steel washers, the maximum punch load used is 3×105N. The plate thickness is 5 mm and percentage penetration is 25. What is the work done during this shearing operation?
- 325 J
- 475 J
- 375 J
- 350 J
Q. A hydraulic press is used to produce circular blanks of 100mm diameter from a sheet o 2mm thickness. If the shear strength of the sheet material is 400N/mm2, the force required for producing a circular blank is
- 8kN
- 25.13kN
- 31.42kN
- 125.66kN
Q. The punching force required in a blanking operation of mild steel sheet is 500 kN. The diameter of blank is increased by 20% and thickness is reduced by 4%, then punching force will be:
- 434 kN
- 576 kN
- 634 kN
- 676 kN
Q. The punching force required in a blanking operation of mild steel sheet is 500 kN. The diameter of blank is increased by 20% and thickness is reduced by 4%, then punching force will be:
- 434 kN
- 576 kN
- 634 kN
- 676 kN