Divisibility Rule for 3 & 9
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An eight digit number divisible by 9 is to be formed by using 8 digits out of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 without replacement.
The number of ways in which can be done is
4(7!)
2(7!)
(36)(7!).
(7!)(33)
- 7
- 1
- 4
- 9
- 1683
- 1793
- 1573
- None of these
- 1463
- 14
- 16
- 17
- 15
Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is :
6
3
4
7
5
- 4
- 7
- 1
- 2
- 5
- 2
- 6
- 7
- 640
- 940
- 840
- 740
- None of these
I. 1000≤n≤1200
II. Every digit in n is odd
Then how many elements of S are divisible by 3?
- 9
- 10
- 11
- 12
How many numbers of digits can be formed from the digits of the number ?
The remainder when is divided by is?
- 9
- 0
- 3
- (a) or (b)
What will be the least number which when doubled will exactly be divisible by 12, 18, 21 and 30?
None of these
196
630
1260
2520
8776
12503
none of these
7499
- 3
- 6
- 9
- 8
- divisible by 8
- equal to 27
- divisible by 11
- all of these
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
74
94
184
364
None
- can't be determined
- 0
- 1
- 2
Choose the most appropriate option to replace (?).
34, 18, 10, ?
- 8
- 7
- 6
- None of the above
- 5
- 25 times, 89
- 21 times, 97
- 22 times, 97
- 19 times, 97
A prime number x greater than 100 leaves a remainder y on division by 26. How many values can y take?
8
9
7
6
Write the odd numbers between
- 3
- 7
- 2
- 6
- 0
- 6
- 1
- 3
- 7
- 5
- 6
- 9
- 3
- 4
- 6
- 7
- 2
- 39
- 72
- 81
- 108
- 55
- 436
- 2195
- 32
- 9
- None of these
- 0
- 8
- 7
- none of these