Divisibility Rule for Powers of 2 & 5
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A two – digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
24
42
81
None of these
18
- 141960
- none of these
- 152295
- 600
- 28
- 27
- 26
- 25
- 1
- 2
- 3
- 4
- 411
- 412
- 410
- none of these
- 98550
- 97560
- 96000
- 99550
There are three events X, Y and Z, out of which only one must happen. If the odds are 8:3 against X, 5:2 against Y, the odds against Z must be:
34:43
43:34
None of these
8:11
7:5
- 50, 500
- 50, 250
- 50, 000
- 49, 500
- 477
- 594
- 653
- None of these
What is the remainder of 1421×1423×1425 when divided by 12 ?
0
1
3
2
- 2
- 4
- 1
- None of these
1! + 2! + 3! + ... + 70!?
- 5
- 1
- 3
- 6
- 736
- 1008
- 1356
- 894
X is a two – digit number, if it is known that its unit’s digit exceeds its ten’s digit by 2 and that the product of the given number and the sum of its digits is equal to 144. Then the number is:
24
26
42
46
29
- 99550
- 97560
- 98550
- 96000
- 98545
- can't be determined
- none of these
- 103
- 38
- 0
- 10
- 20
- 90
The remainder obtained when (13+23+33+43+……1003) is divided by 9 is
1
0
3
2
- 1
- 0
- 3
- 2
(i) 100 ≤N≤500
(ii) N is even
(iii) N is divisible by either 2 or 3 or 4 but not by 7.
How many elements are there in set A?
- 170
- 173
- 171
- 172
The remainder when 786786 is divided by 7 is
- 55
- 0
- 44
- 1
- 0
- 1
- 100
- 9900
- none of these
- 0
- 6
- 3
- can't be determined
The remainder obtained when 26812681 is divided by 3 is
0
1
2
3
There are three events X, Y and Z, out of which only one must happen. If the odds are 8:3 against X, 5:2 against Y, the odds against Z must be:
7:5
43:34
None of these
8:11
- 1
- 5
- 11
- 2
- 296
- None of these
- 696
- 496