Molarity
Trending Questions
Determine the percentage of oxygen in ammonium nitrate.
The volume-temperature relationship is given by _______ .
Dalton's Law
Gay Lussacs Law
Boyle's Law
Charle's Law
(Given, Atomic mass of sulphur =32 u and NA=6.022×1023)
- 4.022×1015 molecules
- 6.022×1022 molecules
- 3.76×1022 molecules
- 3.76×1030 molecules
Select True or False:
Molarity of a solution depends upon temperature.
True
False
Solution of 100 ml water contains 0.73 g of Mg(HCO3)2 and 0.81 g of Ca(HCO3)2. Calculate the hardness in terms of ppm of CaCO3.
102 ppm
103 ppm
104 ppm
5 × 103 ppm
29.2% (w/W) HCl stock solution has a density of 1.25 g mL−1. The molecular weight of HCl is 36.5 mol−1. The volume (mL) of stock solution required to prepare a 200 mL solution 0.4 M HCl is:
- 0.1 M
- 0.2 M
- 0.05 M
- 0.25 M
- 0.125 mol; 7.32 g
- 7.32 mol; 0.125 g
- 0.125 mol; 0.125 g
- 7.32 mol; 7.32 g
- WV×22400
- VW×22.4
- (W−V)×22400
- W×1V×22400
- 7.45 N
- 0.38 N
- 0.25 N
- 1.75 N
- 3.011×1020
- 6.022×1021
- 6.022×1020
- 3.011×1019
This section contains 1 Assertion-Reason type question, which has 4 choices (a), (b), (c) and (d) out of which ONLY ONE is correct.
इस खण्ड में 1 कथन-कारण प्रकार का प्रश्न है, जिसमें 4 विकल्प (a), (b), (c) तथा (d) दिये गये हैं, जिनमें से केवल एक सही है।
A : At low pressure CO2(g) shows more negative deviation than O2(g).A : निम्न दाब पर O2(g) की अपेक्षा CO2(g) अधिक ऋणात्मक विचलन दर्शाती है।
R : van der Waals constant ‘b’ for CO2(g) is more than van der Waals constant ‘b’ of O2(g).
R : O2(g) के लिए वाण्डरवाल्स नियतांक ‘b’, की अपेक्षा CO2(g) के लिए वाण्डरवाल्स नियतांक ‘b’ अधिक होता है।
- Both (A) and (R) are true and (R) is the correct explanation of (A)
(A) तथा (R) दोनों सही हैं तथा (R), (A) का सही स्पष्टीकरण है - Both (A) and (R) are true but (R) is not the correct explanation of (A)
(A) तथा (R) दोनों सही हैं लेकिन (R), (A) का सही स्पष्टीकरण नहीं है - (A) is true but (R) is false
A) सही है लेकिन (R) गलत है - (A) is false but (R) is true
(A) गलत है लेकिन (R) सही ह
(IIT-JEE-2013)
- 1.75 M
- 1.00 M
- 0.975 M
- 0.875 M
How many moles of sodium chloride are present in 250mL of a 0.50 M NaCI solution?
- 0.125mol
- 0.075mol
- 0.150mol
- 0.02mol
- 3.2
- 22.4
- 11.2
- 5.6
- 17
- 34
- 15
- 1.7
- 3
- 2
- 1
- 4
H2 gas produced by the reaction is collected over water. If 0.3 g of Zn are consumed at 270 in the reaction, calculate the volume of hydrogen produced. (Given: Barometric reading=750mm, Aqueous tension at 27 =25 mm, Atomic weight of Zn=65.4).
- 23.48
- 46.96
- 71
- 53.78
- 2.5
- 5
- 10
- 20
- 4.5g
- 0.45g
- 6g
- 7.72g
- NaOH=40gmol−1
- Na2OH=63gmol−1
- Na(OH)2=57gmol−1
- none of the above
Which of the following are molecules of compounds?
(I) Carbon dioxide
(II) Chlorine gas
(III) Hydrogen Chloride
All I, II and III
Both I and III
Only II
Only I
Molar mass of liquid is 280 and its density is 1.4g/mL
- 0.4L
- 1.6L
- 4.8×1023L
- 0.8L
The mole fraction of solvent in a solution having 6 moles of sugar dissolved in 18 moles of solvent is
0.50
0.25
0.75
1.00