Any Point Equidistant from the End Points of a Segment Lies on the Perpendicular Bisector of the Segment
Trending Questions
In the given figure, AB = BC and AC = CD. Find the ratio of ∠BAD: ∠ADB.
1: 3
3 : 2
3 :1
2:3
If and are the sides of a triangle such that , then the angles opposite to the side is
or
or
or
or
AB is a line segment and P is its mid-point. D and E are points on the same side of
AB such that ∠BAD=∠ABE and ∠EPA=∠DPB (See the given figure). Show that
ΔDAP≅ΔEBP
Question 3
AD and BC are equal perpendiculars to a line segment AB.
Show that CD bisects AB.
In ΔABC and ΔPQR, if AB=AC, ∠C=∠P and ∠B=∠Q. The two triangles are
(A) isosceles but not congruent
(B) isosceles and congruent
(C) congruent but not isosceles
(D) neither congruent nor isosceles
In ΔPQR, PD⊥QR such that D lies on QR. If PQ = a, PR = b, QD = c and DR = d, then prove that (a+b) (a-b) = (c+d) (c-d).
The length and breadth of a rectangle are and respectively. Its area will be ,
AD is an altitude of an isosceles triangles ABC in which AB = AC. Show that
AD bisets BC
ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see the given figure). If AD is extended to intersect BC at P, show that
ΔABP≅ΔACP
![](https://search-static.byjusweb.com/question-images/byjus/207422_3c4e0ded8cbfb3f571da00e2776625abfc6fa5be20160920-19130-1f8q00c.png)
In a andis a point on sidesuch that . Prove that .
Find the area of the rectangles whose sides are: and
An equilateral triangle ABC is inscribed in a circle with centre O. Then, ∠BOC is equal to ___.
- 30∘
- 120∘
- 60∘
- 90∘
Find the area of the rectangles whose sides are: and
The locus of centers of all circles passing through two given points A and B is ______.
the perpendicular bisector of the line segment AB.
the bisector of the line segment AB.
any line perpendicular to the line segment AB.
a line parallel to the line segment AB.
A perpendicular bisector divides a line into two equal halves.
True
False
∠OBC is 90∘. Then, B must be the midpoint of CE. (True/False)
True
False
In the given figure $ △ABC$ is a right-angled triangle at $ B$.
Let $ D$ and $ E$ be any points on $ AB$ and $ BC$ respectively.
Prove that $ {\left(AE\right)}^{2} + {\left(CD\right)}^{2} = {\left(AC\right)}^{2} + {\left(DE\right)}^{2}$
In a ΔABC, it is given that AB = AC and AD is drawn perpendicular to BC. D is not the mid-point of BC.
True
False
- 120 sq.units
- 160 sq.units
- 96 sq.units
- 80 sq.units
Show that
(i) AB2=BC.BD
(ii) AC2=BC.DC
(III) AD2=BD.CD
![379426_394fd31fd3c8414e81d762f8d6c10ee4.png](https://search-static.byjusweb.com/question-images/toppr_ext/questions/379426_394fd31fd3c8414e81d762f8d6c10ee4.png)
(i)OA2+OB2+OC2−OD2−OE2−OF2=AF2+BD2+CE2,
(ii) AF2+BD2+CE2=AE2+CD2+BF2.
![785673_bbc6c3a95868420bba0f8996a1d7ff45.png](https://search-static.byjusweb.com/question-images/toppr_invalid/questions/785673_bbc6c3a95868420bba0f8996a1d7ff45.png)
![1878408_9f112d535b7b499ebaf599d5dd2f86c6.png](https://search-static.byjusweb.com/question-images/toppr_invalid/questions/1878408_9f112d535b7b499ebaf599d5dd2f86c6.png)
In a right-angled triangle, one of the acute angles measures 53°. Find the measure of each angle of the triangle.
(3 marks)
(i) △ABD∼△ECF
(ii) AB×EF=AD×EC
![1008981_52cd7f03df30439585fc215cfddb28d6.png](https://search-static.byjusweb.com/question-images/toppr_invalid/questions/1008981_52cd7f03df30439585fc215cfddb28d6.png)
- angle bisector
- perpendicular bisector
- area
- angle