Applications of Cross Product
Trending Questions
Q. Let →A be vector parallel to line of intersection of planes P1 and P2 through origin. P1 is parallel to the vectors 2^j+3^k and 4^j−3^k and P2 is parallel to ^j−^k and 3^i+3^j, then the angle between vector →A and 2→i+→j−2^k is
- π2
- π4
- π4
- 3π4
Q. If →a and →b are the two sides of a triangle, then the area of triangle will be given by |→a×→b|
- True
- False
Q. A unit vector making an obtuse angle with x – axis and perpendicular to the plane containing the points ^i−2^j+3^k, 2^i−3^j+4^k and ^i−5^j+7^k,
- Also makes and obtuse angle with y - axis
- Also makes an obtuse angle with z - axis
- Also makes an obtuse angle with y and z axis
- None of the above
Q. The area enclosed by the points (1, 1), (-1, 1), (-1, -1) and (1, -1) is
Q.
If →r×→b=→c×→b and →r.→a=0 where →a=2^i+3^j−^k, →b=3^i−^j+^k and →c=^i+^j+3^k, then →r is equal to
12(^i+^j+^k)
2(^i+^j+^k)
2(−^i+^j+^k)
12(^i−^j+^k)
Q. The value of b such that the scalar product of the vector ^i+^j+^k with the unit vector parallel to the sum of the vectors 2^i+4^j+5^k and b^i+2^j+3^k is one, is
- -1
- 1
- 0
- -2
Q. If a is any vector then (a×^i)2+(a×^j)2+(a×^k)2 =
- 3a2
- 4a2
- a2
- 2a2
Q. If →AB=3^i−2^j+^k, →BC=^i+2^j−^k, →CD=2^i+^j+3^k, →OA=^i+^j+^k, then the position vector of →OD is
- 7^i−2^j−3^k
- 7^i−2^j+3^k
- 7^i+2^j−3^k
- 7^i+2^j+4^k
Q. The area of the parallelogram whose diagonals are ^i−3^j+2^k, −^i+2^j is
- 4√29sq.units
- 12√21sq.units
- 10√3sq.units
- 12√270sq.units
Q. If 2^i+3^j+4^k and ^i−^j+^k are two adjacent sides of a parallelogram, then the area of the parallelogram will be
- Cannot be calculated from the given data
- none of the above
Q. The vector area of the triangle with vertices ^i+^j+^k, ^i+^j+2^k, ^i+2^j+^k is
- ^i
- −^i
- 12i
- −12i
Q. If the vectors →a, →b and →c form the sides BC, CA and AB respectively of a Δ ABC, then
- →a. →b=→b. →c=→c. →a
- →a×→b+→b×→c=→c×→a=→0
- →a.→b+→b.→c+→c.→a=0
- →a×→b=→b×→c=→c×→a
Q. The area of a triangle is 5. Two of its vertices are (2, 1) and (3, -2). The third vertex lies on y=x+3. Find the third vertex.
Q. If G is the centroid of ΔABC and O is any point then ¯¯¯¯¯¯¯¯OA+¯¯¯¯¯¯¯¯OB+¯¯¯¯¯¯¯¯OC=
- ¯¯¯¯¯¯¯¯¯OG
- 2¯¯¯¯¯¯¯¯¯OG
- 3¯¯¯¯¯¯¯¯¯OG
- 4¯¯¯¯¯¯¯¯¯OG