Area of Triangle Given Its Vertices
Trending Questions
The points (5, - 2), (6, 4) and (7, - 2) are the vertices of an _________ triangle.
The point A(-6, 10), B(-4, 6) and C(3, -8) are collinear such that AB=29AC.
The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is
(A) 14
(B) 28
(C) 8
(D) 6
Find the value of 'k', for which the following points are collinear.
(ii) (8, 1), (k, -4), (2, -5)
If the coordinates of two points A and B are (3, 4) and (5, – 2) respectively. Find the coordinates of any point P, if PA = PB and area of △PAB = 10
- 2
- √5
- 1
- 3
Find the coordinates of the point Q on the X-axis which lies on the perpendicular bisector of the line segment joining the points A(-5, -2) and B(4, -2). Name the type of triangle formed by the point Q, A and B.
- False
- True
A question was asked in a class
”The points A(5, 5), B(4, 4) and C(3, 3) form which triangle?”.
Unfortunately, no student could get it right.
What type of triangle will be formed if the points are joined ?
Scalene
Isosceles
The three points do not form a triangle.
Right angled
The points A(-a, b), B(-a, c) and C(a, c) form the vertices of a triangle. Which of the following is true?
- The triangle is equilateral.
- ΔABC is a right angled triangle, right angled at A.
- Area of the triangle = b(a - c)
- Area of the triangle = a(c - b)
The points A(3, 1), B(12, -2) and C(0, 2) cannot be vertices of a triangle.
Find the area of the quadrilateral whose vertices, taken in order, are (-4, -2), (-3, -5), (3, -2) and (2, 3).
Refer to the following figure. If we were given the coordinates of A, E and B and the lengths of ED, DC and BC, how would you go about finding the area of this figure, pick the easiest way.
Break the fig. into ΔAEB and trapezium EBCD
Break the fig. into ΔAEB, ΔEAB and ΔBDC
Break the fig. into trapeziums EDAX and AXCB where X is
a point on DC such that AX is perpendicular to AX.Cant say
Find the area of the figure:
- 24
- 25
- 26
- 27
m=
(Enter in the form a/b if you obtain a fraction)
Find the value of m if the points A(5, 1), B(-2, -3) and C(8, 2m) are collinear
m =
(Enter in the form a/b if you obtain a fraction)
The area of a quadrilateral whose vertices taken in order are (–4, –2), (–3, –5), (3, –2) and (2, 3) is _______.
26 sq. units
30 sq. units
28 sq. units
27 sq. units
What is the area of a triangle whose vertices are (a , b + c), (a, b - c) and (-a, c)?
4ac
2ab
2ac
4ab
The area of a triangle is 5 square units. Two of its vertices are (2, 1) and (3, -2) and the third vertex lies on y = x + 3, the third vertex is
(3, 4)
(52, 132)
(72, 132)
- (−32, 32)
What is the area of this trapezium?
ED and BC are perpendicular to DC. ED = a, BC = b, DC = c
(1/2)(c+b)(b+a)
(1/2)c(a+b)
(1/2)a(c+b)
(1/2)b(c+a)
- equilateral
- isosceles
- right-angled
- scalene
- 1 sq. units.
- 1.5 sq. units.
- 2 sq. units.
- 0.5 sq. units.
- 12×MN×NO
- 12×MN×MO
- 12×MO×NO
- MN×NO
The area of a triangle having vertices (a, b+ c), (b, c + a) and (c, a + b) is ___.
0
a2 + b2 + c2
1
a + b + c
- 3
- 2
- 32
- 1
If 2 triangles have the same height, the ratio of their areas is equal to the
Ratio of heights
1
Ratio of any 2 sides
Ratio of corresponding bases