Congruency Criterion for Triangles AAS, ASA, SSS, SAS
Trending Questions
Q.
Prove the converse of mid-point theorem.
Q. Question 16
D, E and F are respectively the mid-points of the sides AB, BC and CA of a ΔABC. Prove that by joining these mid-points D, E and F, the ΔABC is divided into four congruent triangles.
D, E and F are respectively the mid-points of the sides AB, BC and CA of a ΔABC. Prove that by joining these mid-points D, E and F, the ΔABC is divided into four congruent triangles.
Q. Question 7 (iii)
P and Q are respectively the mid-points of sides AB and BC of a triangle ABC and R is the mid-point of AP, Show that:
ar(ΔPBQ)=ar(ΔARC).
P and Q are respectively the mid-points of sides AB and BC of a triangle ABC and R is the mid-point of AP, Show that:
ar(ΔPBQ)=ar(ΔARC).
Q.
If △ABC ≅ △DEF by SSS congruence, then, which of the following options is correct?
AB = DE, BC = FE, CA = FD
AB = DE, BC = FE, C = F
AB = FD, BC = DE, CA = FE
AB = EF, BC = FD, CA = DE
Q. Each diagonal of a parallelogram divides it into two congruent triangles.
- False
- True
Q. In the following figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F,
Show that ar(BDE)=12ar(BAE)
Show that ar(BDE)=12ar(BAE)
Q. D, E, and F are respectively the mid-points of the sides AB, BC and CA of a ΔABC. Triangles are formed by joining these mid-points D, E and F. Which among the following is true?
- ΔEFD≅ΔCFE
- ΔDEF≅ΔEDB
- All the above
- ΔADF≅ΔEFD
Q. The opposite sides of a parallelogram are equal is proved using the postulate
- ASA
- SSS
- SAS
Q. Question 5 (iii)
In the following figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that:
(iii) ar(ABC) = 2ar(BEC)
In the following figure, ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that:
(iii) ar(ABC) = 2ar(BEC)
Q. I chapter 9 their is a theorem 1 known as parallelogram on the same Base and between the Same parallel are equal in area in ncert book of class 9 this theorem is proved by using ASA but in byjus it is proved by AAS which solution is right
Q.