Nature of Roots
Trending Questions
Q. The roots of the equation px^2-2(p+2)x+3p=0 are alpha and beta .If alpha- beta=2, calculate the value of Alpha, beta and p
Q. If the roots of the equation (a²+b²)x² -2b(a+c)x + (b²+c²) = 0 are equal, then
A. 2b = a+c
B. b² = ac
C. b = 2ac/ a+c
D. b = ac
Q. 64.Product of two roots x4 - 11x3 + kx2 + 269x - 2001 is -69 , then find the value of k
Q. the value of a for which the equation (1-a^2)x^2 + 2ax -1 =0 has roots belonging to (0, 1) is
Q. If roots of quadratic equation x^2+ax+b+1=0 are positive integers then a^2+ b^2 can be equal to
A. 170
B. 37
C. 61
D. 19
Q.
When the square of a number is decreased by 15, it is equal to twice the original number. Find the possible values of the number.
8, 7
5, -3
9, 6
2, -7
Q.
Question 2 (iv)
Write whether the given statement is true or false. Justify your answer.
Every quadratic equation has at most two roots.
Q. 48. If (a, 0) is a point on a diameter of the circle x²+y²=4 then x²-4x-a²=0 must have : A. Exactly one real root in [-9/10, 1/10] B. Exactly one real root in [4, 49/10] C. Exactly one real root in [0, 2] D. Two distinct real roots in [-1, 5]
Q. The quadratic equation 11/4x^2 - 11(p+q)x+(10p^2 +24pq+10q^2) =0, where pis not equal to +or-q has what type of roots
Real and equal
Real and distinct
No real roots
Q. Find the value of k so that the quadratic equation has equal roots:
(k+3)x² + 2(k+3)x + 4 = 0
Q. If x^2-2px+q=0 has two equal roots then the equation (1+y)x^2 -2(p+y)x +(q+y)=0 will have real and distinct roots when
Q. The roots of following equation \sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=1 ar
Q. (p+4)x^2+(p+1)x+1=0 find the value of p if the equation has equal roots
Q. If alpha, beta are roots of ax2 + bx + c = 0, then the equation ax2 - bx (x - 1) + c(x - 1)2 = 0 has roots
1) alpha/(1-alpha), beta/(1-beta)
2) (1- alpha)/alpha, (1-beta)/beta
3) alpha/(1+alpha), beta/(1+beta)
4) (1+alpha)/alpha, (1+beta)/beta
Q. If the roots of the equation (a²+b²)x² -2(ac+bd)x + (c²+d²) = 0 are equal then prove that a/b = c/d.
Q.
Find the value of a for which the equation has coincident roots
a^2x^2+2(a+1)x+4=0
Q. {m^2+n^2}x^2 - 2{mp+nq}x + p^2 + q^2
This quadratic equation has equal roots. Prove that mn = √pq
Q. Solve the following quadratic equation by factorization method
x2−5x−36=0
x2−5x−36=0
Q. Show that the equation [a-2] x^2 + [2-b]x + [b-a] = 0 has equal roots , if 2a = b+2
Q. . If the roots of the equation (b-c) x2 + (c-a) x + (a-b) = 0 are equal, then prove that
2b = a+c.
Q. the values of k for which the eqn |x|^2(|x|^2-2k+1)=1-k^2 has 1.no real root k belongs to
2.exactly 2 roots
3.repeated roots when k belongs to
Q. if alpha and beta are the roots of the quadratic equation 3 x square - 4 x + 1 is equal to zero then find the quadratic equation whose roots are
1) alpha/beta and beta/alpha
2) (alpha)^2/ beta and (beta)^2/ alpha
Q. If the equation x^2(a^2+b^2)-2b(a-c)x+b^2+c^2=0 has equal roots , then
A.2b=ac
B.b^2=ac
C.b=2ac/(a+c)
D.b=ac
Q. Find p and q, If the equation 2x2+4xy−py2+4x+qy+1=0. represents a pair of perpendicular line.
Q. If α, β and γ are the real roots of a³ − 6a²+ 3a + 1 = 0, determine the sum of possible
values of α²β + β²γ + γ²α.
Q. If (1 + k)x2 – 4x – 1 + k = 0 has real roots tanα and tanβ, then
Q. Assertion :If one root is √3−√2, then the equation of lowest degree with rational coefficients x4−10x2+1=0 Reason: For polynomial equation with rational coefficients irrational roots occurs in pairs.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct , but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
Q. 34. If the equation x⁴-4x³+ax²+bx+1=0 has 4 positive roots, then the value of (|a|+|b|)/(a+b) is. 5/3/-5/-3
Q. The equation of locus of P, if A=(4, 0), B(−4, 0) and |PA+PB|=4 is
- 3x2−y2=12
- x2+y2=4
- x2+3y2=20`
- 3x2+y2=9
Q. If P(x) is a polynomial of degree less than or equal to 2 and S is the set of all such polynomials so that P(1)=1, P(0)=0 and P′(x)>0 ∀ x∈[0, 1], then
- S=ϕ
- S=(1−a)x2+ax for 0<a<2
- (1−a) x2+ax for a∈(O, ∞)
- S={(1−a)x2+ax for 0<a<1