Nth Term of A.P

Q. In the sum fo first n terms of an A.P. is $c{n}^2$ then the sum of squares of these n terms is

1. $\frac{n(4n^2-1)c^2}{6}$
2. $\frac{n(4n^2+1)c^2}{3}$
3. $\frac{n(4n^2-1)c^2}{3}$
4. $\frac{n(4n^2+1)c^2}{6}$

Q. In the sum fo first n terms of an A.P. is $c{n}^2$ then the sum of squares of these n terms is

1. $\frac{n(4n^2-1)c^2}{6}$
2. $\frac{n(4n^2+1)c^2}{3}$
3. $\frac{n(4n^2-1)c^2}{3}$
4. $\frac{n(4n^2+1)c^2}{6}$