Number of Zeroes
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If a polynomial cuts the x-axis at 3 points and y-axis at 2 points, then the number of zeroes of the polynomial would be
If a polynomial of the form y = f(x) cuts the X-axis at 3 points and Y-axis at 2 points, then the number of zeroes of the polynomial would be
If f(x) = (x - a)(x - b) , then if a and b are the zeros of the polynomial f(x), f(a) = f(b).
True
False
Find the zero the polynomial,
If k and 2k are zeros of f(x)=x3+4x2+9kx=90, find k and all three zeros of f(x).
K = 1, roots = -3, -6, -5
K = -3, roots = -3, -6, 5
K = -3, roots = -3, 6, -5
K = 3, roots = -3, -6, 5
- 7
- 5
- 3
- 1
The maximum number of zeroes the polynomial x7+x5+x3+x+1 can have is _______.
0
6
5
7
- 5
- 6
- 3
- 4
p(x)=x5+4x4+3x2+2x+1
have at most?
- 5
2x2+x−4=0
- √35−14 or x=−√35−14
- √33−12 or x=−√33−12
- √35−12 or x=−√35−12
- √33−14 or x=−√33−14
- x6+4x3+5
- x16+24x3
- x99+1
- x100−1
x10+x6+x4+x+1
- 6
- 5
- 4
- 10
- 7
- 5
- 3
- 1
- 7
- 5
- 3
- 1
In the method to find the roots of the quadratic equation 3x2- 2√6 x + 2 = 0 using factorization method, the given equation is reduced to the form (ax+b)(cx+d). The values of a and d are
- √3, √6
√3, -√2
- √7, √6
√3, √6
- x6+4x3+5
- x16+24x3
- x99+1
- x100−1
In the method to find the roots of the quadratic equation 3x2- 2√6 x + 2 = 0 using factorization method, the given equation is reduced to the form (ax+b)(cx+d). The values of a and d are
√3, -√2
√3, √6
- √3, √6
- √7, √6
- x16+24x3
- x100−1
- x99+1
- x6+4x3+5
Find the roots of the quadratic equation √2x2+7x+5√2=0 using factorisation method.
5√2 and - √2
−5√2 and √2
5√2 and √2
−5√2 and – √2
According to the adjoining graph, the product of the zeroes of the polynomial will be
negative
zero
cannot be determined
positive
p(x)=x5+4x4+3x2+2x+1
have at most?
- 5
- 7
- 5
- 3
- 1
- 7
- 5
- 3
- 1
\( 2x^2 + x - 4 = 0\)