Perpendicular from the Center to a Chord Bisects the Chord
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Q.
Two equal circles of radius r intersect such that each passes through the centre of the other. The length of the common chord of the circles is
√r
√2rAB
√3r
√32r
Q. Find the length of a chord which is at a distance of 4 cm from the centre of the circle of radius 6 cm.