Properties of Parallelograms
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Calculate the area of the whole quadrilateral.
Prove that if both pairs of opposite angles of a quadrilateral are equal, then it is a parallelogram. [3 MARKS]
If AD is median of ΔABC and P is a point on AC such that area (ΔADP) : area (ΔABD) = 2 : 3, then ar(ΔPDC) : ar(ΔABC) is
1 : 5
1 : 6
2 : 5
3 : 5
In the given figure, ABCP is a parallelogram and P is the mid point of CD. Then find which of the following option is correct?
OA=12CD
PD=AP
AP=12BC
OB=12BD
Show that ar(BDE)=12ar(BAE)
Given, BC = 5 cm and the corresponding altitude AP = 8 cm. Find the area of the parallelogram ABCD.
[2 Marks]
Points A(0, 0), B(4, 0), C(6, 6) and D(2, 6) are joined to form quadrilateral ABCD. Point C(6, 6) and point B(4, 0) are joined to point F(8, 0). The quadrilateral DBFC is now completed. Which of the following is correct?
Area of quad ABCD = 1 × Area of quad DBFC
Area of quad ABCD = (1/4) × Area of quad DBFC
Area of quad ABCD = (1/2) × Area of quad DBFC
Area of quad ABCD = 2 × Area of quad DBFC
Show that ar(BDE)=12ar(BAE) [4 MARKS]
In the parallelogram, D is the mid point of side PQ. Which of the following options is NOT true?
PQ = RS
PD = 12 RS
DQ = 12RS
PQ = 3PD
The area of triangle with vertices A(x1, y1), B(x2, y2) and C(x3, y3) is:
12[x1(y2−y3)+x3(y3−y1)+x1(y1−y2)]
- All of the above.
12[x2(y2−y3)+x2(y3−y1)+x3(y1−y2)]
- 12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Area (ΔABE) = 14 Area (ΔABC).
In a triangle ABC, E is the mid-point of median AD. Show that ar (ΔBED) = 14ar(ΔABC) [2 MARKS]
ABC is a triangle in which E is mid-point of median AD. Which of the following is not true?
area of ΔBED=14 area of ΔABC
area of ΔBED = area of ΔBAE
area of ΔABD = area of ΔADC
area of ΔBED=12 area of ΔABC
- True
- False
D, E and F are respectively the mid-points of the sides BC, CA and AB of triangle ABC Show that BDEF is a parallelogram.
State which statement is/are true of the following figure.
12 × area of AFEB = area of Δ DEF
area of Δ ABE = area of Δ DEF
area of Δ AED = 12 × area of ABCD
All of the above