Quotient Law
Trending Questions
Q.
Question 6(ii)
Evaluate:
(58)−7×(85)−4
Q. The value of the expression
(0.3)13(127)14(9)16(0.81)23(0.9)23(3)−12(13)−2(243)−14
(0.3)13(127)14(9)16(0.81)23(0.9)23(3)−12(13)−2(243)−14
- 0.3
- 0.9
- 1.27
- 0.09
Q.
The expression will be represented in ascending power of as
Q.
Question 3(i)
Find the value of:
(30+4−1)×22
Q. (1×103)+(2×102)+(3×100)+(1×10−1)+(2×10−2)=
- 123.12
- 1230.12
- 1230.21
- 1230.21
Q.
Simplify
(0.3)13(127)14(9)16(0.81)23(0.9)23(3)−12(13)−2(243)−14
0.3
0.9
1.27
0.09
Q.
((2)2)2× (33 ÷42) ÷ 32 is equal to
3
1
4
27
Q. If log225log15=logx, then the value x is equal to
- 120
- 65
- 95
- 100
Q.
Simplify 2555
75
35
105
1010
Q.
Simplify (25÷28)5×2−5
1220
12(−15)
12(−5)
1210
Q.
am ÷ an = amn
True
False
Q.
If, x=(−45)30÷ (−45)28 and y=(−45)2×(−45)3, find the value of (x3÷y)2
−1625
625
1625
616
Q.
Solve :
Q. If c2+c=−1 then the value of c3−1 is
- 1
- 0
- -1
- 2
Q.
Simplify the following
Q. If a+b+c=9 and ab+bc+ac=26. Find a2+b2+c2.
Q. Simplify, giving answers with positive index:
(4x2y3)3÷(3x2y3)3
(4x2y3)3÷(3x2y3)3
Q. Evaluate : 1a0+b0+c0
- 1a+b+c
- 3
- 1a+1b+1c
- 13
Q. Given log10a=b, express 102b−3 in terms of a.
Q. Simplify
√x6y3÷3√x2y
- 6√x14y7
- 6√x7y7
- 6√x4y7
- 6√x14y3
Q.
Simplify :
(i) (xaxb)a2+ab+b2×(xbxc)b2+bc+c2×(xcxa)c2+ca+a2
(ii) (xax−b)a2−ab+b2×(xbx−c)b2−bc+c2×(xcx−a)c2−ca+a2
Q.
Find the value of x−3, ifx=(100)1−4÷(100)0.
1009
1008
1007
1006
Q. Choose the correct answer from the given four options:
The value of 1022+10201020 is
The value of 1022+10201020 is
- 10
- 1022
- 1042
- 101
Q. Simplify (p−2q+r)2−(−p+2q−r)2
Q. Simplify:
(xaxb)a2+ab+b2×(xbxc)b2+bc+c2×(xcxa)c2+ca+a2
(xaxb)a2+ab+b2×(xbxc)b2+bc+c2×(xcxa)c2+ca+a2