Theorem 2: Perpendicular from the Center to a Chord Bisects the Chord
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In the given figure, lengths of the chords AB and CD are 12 cm and 18 cm respectively and distance between them is 15 cm. Find the radius of the circle.
None of these
√119 cm
√113 cm
√117 cm
In the given figure, radius of the circle is 5 cm and perpendicular distance from the centre of the circle to the chord, AC is 3 cm.
Find the length of the chord, AC.
4 cm
5 cm
7 cm
8 cm
Two circles of radii 4 cm and 3 cm intersect at two points and the distance between their centres is 5 cm. Find the length of the common chord.
4.8 cm
2.8 cm
7 cm
5.5 cm
Find the area of trapezium (in cm2).
- 45
- 48
- 49
40
The length of the common chord of two intersecting circles is 30 cm. If the diameters of these two circles are 50 cm & 34 cm, the distance between their centers is ____ cm.
30
- 24
- 32
- 28
S1: AM=AP2, BN=BP2
S2: OO′=AM+BN
Choose the correct option.
Only S1 is true.
Only S2 is true.
Both statements are true.
S1 is true & S2 is false.
The perpendicular to a chord from the centre of the circle divides the chord in ratio of
1:1
1:4
1:2
1:3
An equilateral triangle ABC, whose side is 6 cm, is inscribed in a circle. Find the radius of the circle.
2√2 cm
2√3 cm
3√3 cm
3 cm
Two circles of radii 5 cm and 6 cm with common centre are drawn. There is a line AB such that it is chord to both the circles. CD=8 cm. Find the distance of the chord from centre and the length of AC respectively.
2, 2.35
2.35, 2
3, 2
2.16, 2.35
What is the relation between AM & MB in the given figure?
AM = MB
AM = 2MB
2AM = MB
3AM = 2MB