Theorem 4: Triangle and Parallelogram
Trending Questions
What is Inradius?
Perpendicular distance between the incentre and any of the side of the triangle
Half of the length of shortest side of the triangle
Half of the length of longest side of the triangle
Perpendicular distance between incentre and and any of the vertex of the triangle
In parallelogram ABCD, if ∠A = 2x + 15o, ∠B = 3x - 25o, then value of x is:
89o
38o
91o
34o
If P and Q are any two points lying respectively on the sides DC and AD of a parallelogram ABCD then show that ar(△APB)=ar(△BQC).
M is the midpoint of side AB of a parallelogram ABCD.If ar(AMCD) =24 cm2, find ar(△ ABC).
ABCD is a parallelogram and EFCD is a rectangle. AL ⊥ DC, then ar(ABCD) is equal to
ar(∆ADL)
ar(∆FBC)
ar(EFCD)
ar(EALD)
ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA ( see the given figure). AC is a diagonal. Show that:
SR || AC and SR = 12AC.
In the given figure, ABCD is a parallelogram. If area ΔADP=30cm2 and area ΔBCP=24cm2, then area of ||gm ABCD =
- 108
- 96
- 54
- 27
- AB
- AP
- BP
In the given figure, ABCD is a parallelogram whose diagonals intersect at O. The areas of Δ AOD, Δ DOC, Δ COB and Δ BOA are p cm2, q cm2, r cm2 and s cm2 respectively. Then is the statement
p=q≠r=s true?
True
False
If the given figure is a parallelogram, find the values of x and y.
29o, 78o
23o, 23o
29o, 73o
23o, 78o
In the given figure, ABCD is a parallelogram. P and Q are midpoints of AB and AD respectively. Area Δ CPQ : Area of parallelogram ABCD is equal to
3 : 5
3 : 8
5 : 8
1 : 8
In the given figure area of parallelogram ABCD is 160 cm2, then the area of Δ DAC is
240 cm2
120cm2
80 cm2
40 cm2
In a given figure, BE is a median of △ABD. If the area of parallelogram ABCD is 24 cm2. Then the area of △ABE is:
- 10 cm2
- 6 cm2
- 8 cm2
- 12 cm2
In the given figure, ABCD is a parallelogram. E is a point in CD. AE and BC are produced to meet at F.
If area of ΔADF=45 cm2, then area ΔABE =
- 22.5
- 90
- 45
- 75
- PS, QR which are not parallel
- PS, QR which are parallel
- PQ, SR which are parallel
- PR, QS which are not parallel.
(i)PE=FQ?
(ii)ar(trianglePEA)=ar(triangleQFD)?
(iii)ar(triangleAPE):ar(triangleQFD):ar(trianglePFD)
PQRS and ABRS are parallelograms and X is any point on side BR. Then, ar(parallelogram PQRS) is equal to
ar(parallelogram ABRS)
ar(ΔABX)
ar(parallelogram ABRQ)
ar(quad. PSXB)
In the given figure ABCD is a parallelogram. F is a point on DC and FE is the median of Δ ABF. If area of Δ AFE is 15 cm2, then the area of parallelogram ABCD is
30 cm2
45 cm2
60 cm2
150 cm2
In the given figure, ABCD is a parallelogram. If E AND F are midpoints of BC and AD respectively, then which of the following statements is correct?
i) SR∥AC and SR=12AC
ii) PQ=SR
iii) PQRS is a parallelogram.
Δ ABP and parallelogram PABC are between the same parallel lines. If the area of parallelogram PABC is 24 cm2, then the area of Δ ABP is
- 48 cm2
- 32 cm2
- 12 cm2
- 6 cm2
- 1:2
- 6:13
- 5:8
- 4:7
- 90
In the parallelogram AMKR, KA is equal to
2RK
RK
2KS
KS
. If the area of || gram is 120 sq.cm , what is the ar(△) which is between the same base and same parallels?
120 sq cm
240 sq cm
320 sq cm
60 sq cm
(ii) BR=2BQ