Triangles between Same Parallels
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If a triangle and a parallelogram are on the same base and between the same parallels, then:
area of triangle = 14area of parallelogram
area of triangle = 13area of parallelogram
area of triangle = 12area of parallelogram
area of triangle = area of parallelogram
The area of a parallelogram is 338 m square if its altitude is twice the corresponding base determine the base and altitude
ABCD is a parallelogram. E and F are the mid-Points of BC and AD respectively. Show that the segments BF and DE trisect the diagonal AC. [4 MARKS]
The area of isosceles right angled triangle is then the length of the hypotenuse is
In the given figure, ABCDE is a pentagon with AC = 5 cm. A line through B parallel to AC meets DC produced at F. If the altitude of triangle ABC (perpendicular to AC) is 6 cm. Find the area of triangle ACF.
- 5 cm2
- 10 cm2
- 15 cm2
- 30 cm2
If the area of parallelogram ABCD is 54 square units, what is the area of parallelogram ABEF? [Given: O and P are the midpoints of AD and BC respectively]
27 square units
30 square units
33 square units
36 square units
AE || BC and D is the midpoint of BC. If area △ABC = 84 square cm, what is the area of △BDE?
21 square cm
42 square cm
63 square cm
84 square cm
In a parallelogram ABCD, AB = 2 BC. If the length of the altitude corresponding to AB is 10 cm, what is the length of the altitude corresponding to BC?
15 cm
40 cm
10 cm
20 cm
ABCD is a parallelogram. P is any point on CD. If ar(△DPA)=25 cm2 and ar(△APC)=40 cm2, then area(△APB)is
45 cm2
75 cm2
65 cm2
32 cm2
ABCD is a parallelogram and P, Q are the midpoints of DC and AB respectively. Then, area of parallelogram AQPD is equal to area of triangle ADB.
True
False
In this figure AB ∥ DC. Write two pairs of triangles having the same area.
- △ADB and △ACB
- △DCA and △ADB
- △DCA and △DCB
- △ADB and △DCB
are respectively the mid-points of sides of . Find the ratio of the area of and
- 2:1
- 3:1
- 1:2
- 2:3
ABCD is a parallelogram. P is any point on CD. If ar(△DPA) = 35 cm2 and ar(△APC) = 15 cm2, then area of (△APB) is equal to
15 cm2
35 cm2
50 cm2
70 cm2
(i) BDEF is a parallelogram
(ii) ar(DEF)=14ar(ABC)
(iii) ar(BDEF)=12ar(ABC)
In the given figure, ABQP and ABCD are two parallelograms on the same base AB. Area of parallelogram ABCDArea of triangle PAB is equal to:
- 15 cm2
- 35 cm2
- 70 cm2
- 50 cm2
Which among the following is correct?
Parallelograms on the same base and between the same set of parallel lines:
have unequal areas
have the same perimeter
may have equal or unequal areas
have equal areas
If two triangles have equal area and stand on the same base, then the altitudes of the triangle are equal.
True
False
The median of any triangle bisects it into two triangles of equal areas.
True
False
In Δ ABC, DE is parallel to BC. Which of the following are correct?
Area of ∆BEC and ∆ BDC are equal.
(1/2)Area of BDEC = Area of ∆BDC
DE is parallel to BC
All of the above
Show that ar(ΔPBQ)=ar(ΔARC).
- 18 cm2
- 54 cm2
- 48 cm2
- 36 cm2
- 4:9
- 81:16
- 2:3
- 16:81
If AD is median of ΔABC and P is a point on AC such that ar(ΔADP) : ar(ΔABD) = 2 : 3, then ar(ΔPDC) : ar(ΔABC) is ______ .
- 3 : 5
- 1 : 6
- 2 : 5
- 1 : 5
In the rectangle ABCD, O is any point inside the rectangle. If area(△AOD) = 30 cm2 and area(△BOC) = 60 cm2, Find the area of the rectangle ABCD. [2 MARKS]
(i) ar(ACB) = ar(ACF)
(ii) ar(AEDF) = ar(ABCDE)