Area and Volume Expansion
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A piece of metal floats in mercury. The coefficients of volume expansion of the metal and mercury are γ1 and γ2 respectively. If their temperature is increased by ΔT, the fraction of the volume of metal submerged in mercury changes by a factor
(1+γ2ΔT1+γ1ΔT)
(1+γ2ΔT1−γ1ΔT)
(1−γ2ΔT1+γΔT)
γ2γ1
The density of a liquid of coefficient of cubical expansion γ is ρ at 0∘C. When the liquid is heated to a temperature T, the change in density will be
−ρ(1+γT)γT
−ργT(1+γT)
ργT(1+γT)
ρ(1+γT)γT
- Increase
- Decrease
- Remain unchanged
- Have its shape changed
Calculate the increase in the volume of a liquid when heated to 400C. Given that the original volume of liquid is 2 liters and its volume expansion coefficient is .
A one-litre flask contains some mercury. It is found that at different temperatures the volume of air inside the flask remains the same. What is the volume of mercury in the flask? Given the coefficient of linear expansion of glass is 9×10−6 ∘C−1 and the coefficient of volume expansion of mercury is 1.8×10−4 ∘C−1
50 cm3
150 cm3
100 cm3
200 cm3
- 6.66
- 6.86
- 6.33
- 4.66
A glass flask of volume one litre at 0∘C is filled, level full of mercury at this temperature. The flask and mercury are now heated to 100∘C. How much mercury will spill out, if coefficient of volume expansion of mercury is 1.82×10−4 ∘C and linear expansion of glass is 0.1×10−4 ∘C respectively
2.12 cc
21.2 cc
15.2 cc
1.52 cc
A sphere of diameter 7.0 cm and mass 266.5 g floats in a bath of a liquid. As the temperature is raised, the sphere begins to sink at a temperature of 35∘C. If the density of the liquid is 1.527 g/cm3 at 0∘C, find the coefficient of cubical expansion of the liquid. Neglect the expansion of the sphere.
2.32 × 10-4/°C
1.22 × 10-4/°C
8.28 × 10-4/°C
6.36 × 10-4/°C
A glass flask of volume one litre at 0∘C is filled, level full of mercury at this temperature. The flask and mercury are now heated to 100∘C. How much mercury will spill out, if coefficient of volume expansion of mercury is 1.82×10−4/∘C and linear expansion of glass is 0.1×10−4/∘C respectively
21.2 cc
15.2 cc
1.52 cc
2.12 cc
A piece of metal floats in mercury. The coefficients of volume expansion of the metal and mercury are γ1 and γ2 respectively. If their temperature is increased by ΔT, the fraction of the volume of metal submerged in mercury changes by a factor
(1+γ2ΔT1+γ1ΔT)
γ2γ1
(1+γ2ΔT1−γ1ΔT)
(1−γ2ΔT1+γΔT)
You have with you, a mug of 500 mL, and a spoon of length 12 cm, both made of pure aluminum. When the AC in the room brings down the room temperature from 34∘C, to 16∘C you find upon precise measurement, that the spoon got shorter by 0.00499 cms. What will be the new volume of the mug?
501.12 mL
502.3 mL
499.38 mL
498.54 mL
On a hot day in Jaipur, an oil trucker loaded 40 kL (kilolitres) of diesel fuel. On his way to Shimla, he encounters a temperature drop of 20∘C, where he stopped and delivered the entire load. How many litres did he deliver? The γ for diesel is 9.50 × 10−4/∘C and α for his steel truck is 11 × 10−6/∘C. If you find that the volume has decreased, think about who is paying for the "missing” diesel.
39, 240 L
39, 810 L
40, 000 L
40, 126 L
The coefficient of expansion of a crystal in one direction (x-axis) is 2.0×10−6 K−1 and that in the other two perpendicular directions (y and z-axes) is 1.6×10−6 K−1, What is the coefficient of cubical expansion of the crystal?
2.0×10−6 K−1
5.2×10−6 K−1
1.8×10−6 K−1
1.6×10−6 K−1
A gas in an airtight container is heated from 25∘C to 90∘C. The density of the gas will:
( Consider there is a negligible expansion of container)
Increase considerably
Remain the same
Increase slightly
Decrease slightly
2.3 × 106/°C
1.2 × 10-5/°C
1.2 × 105/°C
2.3 × 10-5/°C
I received my favourite cologne, bottled in a metallic flask with a spherical cavity, on my birthday in December. I used it modestly only on special occasions, and found that I have finally emptied the bottle in mid-April, when the temperature had risen by 25∘C from December. If the metal's coefficient of superficial (area) expansion is 46 × 10−5/∘C, how much extra cologne can I refill my bottle with, compared to the initial volume (answer in mL)?
5 mL
2 mL
10 mL
3.5 mL
An aluminium sphere is dipped into water at 15∘C(γaluminium = 69 × 10−6/∘C;γwater=214 × 10−6/∘C). If the temperature is increased, the force of buoyancy:
will increase
will decrease
will stay the same
will increase or decrease depending on the radius of the sphere
A one-litre flask contains some mercury. It is found that at different temperatures the volume of air inside the flask remains the same. What is the volume of mercury in the flask? Given the coefficient of linear expansion of glass is 9×10−6 ∘C−1 and the coefficient of volume expansion of mercury is 1.8×10−4 ∘C−1
50 cm3
100 cm3
150 cm3
200 cm3
Whenever a liquid is heated in a container, expansion in liquid as well as container takes place. If r is the volume expansion coefficient of liquid and is coefficient of liner expansion. Match the entries of Column I and Column II
Column IColumn II(i) Liquid level rises with respect to container(A) g=2a(ii) Liquid level remains same with respect to container(B) 2α<γ<3α(iii) Liquid level drops with respect to container(C) g=3a(iv) Liquid level remains same with respect to ground(D) g>3a
- (i) - (A), (ii) – (C), (iii) – (B), (iv) – (D)
- (i) - (B), (ii) – (C), (iii) – (D), (iv) – (A)
- (i) - (D), (ii) – (A), (iii) – (B), (iv) – (C)
- (i) - (D), (ii) – (C), (iii) – (B), (iv) – (A)
A flask of volume V contains some mercury. It is found that at different temperatures, the volume of air inside the flask remains the same. If γg and γm are the coefficients of cubical expansion of glass and mercury respectively, the volume of mercury in the flask is
γmVγg
γgVγm
(1−γgγm)V
(1−γmγg)V
Expansion during heating:
Occurs only in solids
Increases the weight of a material
Decreases the density of a material
Occurs at the same rate for all liquids and solids
- 0.378 Jg−1K−1
- 0.578 Jg−1K−1
- 0.778 Jg−1K−1
- None of the above
The density of a liquid of coefficient of cubical expansion γ is ρ at 0∘C. When the liquid is heated to a temperature T, the change in density will be
−ργT(1+γT)
ργT(1+γT)
ρ(1+γT)γT
−ρ(1+γT)γT
- 1×10−2M
- 1×10−3M
- 1×10−1M
- 0.64g