Equation of motion
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An electron moving with a velocity of enters into a uniform electric field and acquires a uniform acceleration of in the direction of its initial motion
(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.
(ii) How much distance the electron would cover in this time?
A ball thrown up vertically returns to the thrower after . Find (i) velocity (ii) Maximum height it reaches (iii) Position after
A ball is thrown vertically upwards with a velocity of . Calculate the total time it takes to return to the surface of the earth.
What is the dimensional formula of acceleration?
A car is travelling at 15 m/s. If its velocity increases to 20 m/s in 5 s then find the acceleration of the car.
A ball thrown vertically upward rises to a height of . If the acceleration due to gravity is , calculate the time taken to gain the maximum height?
- 13 m
- 5 m
- 15 m
- 16 m
- 9√2 ms, 9√2 ms
- 16√2 ms, 16√2 ms
- 18 ms, 18 ms
- 40 ms, 40 ms
An object is thrown vertically upwards to a height of . Calculate its time taken by the object to reach the highest point.
- −1.11 ms−2
- 1.11 ms−2
- −1.62 ms−2
- 1.62 ms−2
An express train going towards Delhi is travelling at a speed of 90 kmph. Brakes are applied so as to produce a uniform acceleration of –0.5m s−2 . Find how far the train will go before it is brought to rest.
600 m
725 m
625 m
500 m
An electron moving with a velocity of 5×104ms−1 enters into a uniform electric field and acquires a uniform acceleration of 104ms−2 n the direction of its initial motion.
(ii) How much distance the electron would cover in this time?
- 4 s
20 m - 5 s
25 m - 4 s
24 m - 5 s
30 m
- a=−2 ms−2, t=6 s
- a=−1 ms−2, t=9 s
- a=−2 ms−2, t=9 s
- a=−1 ms−2, t=6 s
- −1.62 ms−2
- 1.62 ms−2
- −1.11 ms−2
- 1.11 ms−2
A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?