Error and Uncertainty
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In the determination of Young’s modulus (Y=4 MLgπl d2) by using Searle’s method, a wire of length L=2m and diameter d=0.5mm is used. For a load M=2.5kg, an extension l=0.25mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurement is:
Due to the errors in the measurement of d and l are the same
Due to the error in the measurement of d is twice that due to the error in the measurement of l
Due to the error in the measurement of l is twice that due to the error in the measurement of d
Due to the error in the measurement of d is four times that due to the error in the measurement of l
Two full turns of the circular scale of a screw gauge cover a distance of on its main scale. The total number of divisions of on its main scale. The total number of divisions on the circular scale is . Further, it is found that the screw guage has a zero error of . While measuring the diameter of a thin wire, a student notes the main scale reading of and the number of circular scale divisions in line with the main scale as . The diameter of the wire is
स्प्रिंग द्वारा संयोजित m व 2m द्रव्यमान के दो गुटकों को एक चिकने क्षैतिज पृष्ठ पर रखा जाता है। 2m द्रव्यमान के गुटके पर एकसमान क्षैतिज बल F दर्शाए अनुसार कार्य करना प्रारम्भ करता है। जब प्रत्येक गुटके का त्वरण समान है, तब स्प्रिंग में प्रसार है
- F3k
- 2F3k
- F4k
- F2k
The main scale reading is 8 cm and vernier coincidence is 4 and negative zero error is 0.02 cm. Then calculate the correct reading:
[2marks]
increasing the total number of divisions on the main scale
decreasing the total number of divisions on the circular scale
increasing the total number of divisions on the circular scale
constructing the gauge with an alloy of iron, tin, and lead
- 0.0158 cm
- 0.00158 cm
- 1.58 μm
- 15.8 μm
- Both
- Systematic errors
- Random errors
- None
The number of significant figures can reduces in
- Multiplication
- Addition
- Subtraction
- Division
(a) Determine the least count of the callipers.
(b) Find the length of the line.
- 36:1
- 1:√6
- √6:1
- 1:36