Area of Triangle Using Coordinates
Trending Questions
Q.
If the coordinates of two points A and B are (3, 4) and (5, -2) respectively. Then, the coordinates of any point P, if PA = PB and area of Δ PAB = 10, are
(7, 5), (1, 0)
(2, 7), (1, 0)
(7, 2), (1, 0)
(7, 2), (- 1, 0)
Q.
The area of the triangle formed by the line and the coordinate axes is:
Q.
The points (3, 3), (h, 0) and (0, k) are collinear if
Q. A=(2, 3, 0) and B=(2, 1, 2) are two points. If the points P, Q are on the line AB such that AP=PQ=QB then PQ=?
- √2
- 2√2
- 6√2
- √8/9
Q. If (−4, 0) and (1, −1) are two vertices of a triangle of area 4 sq. units, then its third vertex lies on
- y=x
- 5x+y+12=0
- x+5y−4=0
- x+5y+12=0
Q. In a triangle ABC, A=(α, β), B=(2, 3), C=(1, 3) and point A lies on line y=2x+3 where α, β∈I. Area of triangle △ABC, Δ is such that [Δ]=5. Possible coordinates of A are (where [.] represents greatest integer function)
- (2, 3)
- (5, 13)
- (−5, −7)
- (−3, −5)
Q. Given a triangle whose vertices are at (0, 0), (4, 4) and (10, 0). A square is drawn in it such that its base is on the x - axis and its two corners are on the 2 sides of the triangle. The area of square is equal to
- 40049
- 40025
- 62516
- 62549
Q.
What is the area of with vertices and ?
Q. The vertices of a triangle OBC are O(0, 0), B(−3, −1), C(−1, −3), then the equation of the line parallel to the side BC and cutting the sides OB and OC and at a distance 12 from the origin is
- x+y−12=0
- x+y−1√2=0
- x+y+12=0
- x+y+1√2=0
Q.
If the area of the triangle formed by the lines y=x, x+y=2 and the line through P(h, k) and parallel to x-axis is 4h2, the locus of P can be
2x−y+1=0
2x+y−1=0
x−2y+1=0
x+2y−1=0