Construction of an Angle of 60 Degrees

Q.

Draw an angle of ${132}^{\circ }$ and construct its bisector. [4 MARKS]

Q.

Your aim is to construct an angle $\angle$ YPX = ${30}^{\circ }$ using a compass and ruler only. What is the total number of arcs to be drawn to construct an angle of ${30}^{\circ }$ after drawing the base ray PX?

1. 4 arcs
2. 3 arcs
3. 5 arcs
4. 6 arcs

Q. How many arcs do we need to construct a ${15}^{\circ }$ angle without using a compass if a ray is given?

1. 8

Q. Which among the following is not the correct step while replicating an angle using compass, ruler and pencil?

1. Draw a line with the straight edge and mark a point on it
2. Draw an arc of any radius, centered at point $O$ of angle $AOB$
3. Using the same radius, draw an arc on the new ray
4. Draw an arc of unit radius, centered at $B$ of angle $AOB$
5. Measure the distance between the points where the arc intersects the arms of angle $AOB$ with the compass

Q. Let $ABC$ be a triangle and let $P$ be an interior point such that $\angle BPC=90$, $\angle BAP=\angle BCP$. Let $M,N$ be the mid-points of $AC,BC$ respectively. Suppose $BP=2PM$. Then $A,P,N$ are collinear ?

1. True
2. False

Q. Jack wants to trisect an angle. At what distance Jack should mark the ruler in order to do so?

1. Any two places
2. 2 cm gap
3. 5 cm from beginning

Q.

For constructing an angle of ${60}^{\circ }$, we need to draw __ arc/arcs.

Q. Nish wants to find the number of arcs used to construct $\angle ABX={30}^{\circ }$ using only a compass and a ruler after drawing the base ray PX. Help her find the number of arcs she makes with the compass.

1. 4

Q. In the process of construction of a ${45}^{\circ }$, a angle would be constructed first.

1. ${100}^{\circ }$
2. ${90}^{\circ }$
3. ${22.5}^{\circ }$
4. ${120}^{\circ }$

Q. Construct a right angled $△ABC$ with $\angle B={90}^{\circ },BC=5cm$ and $AC=10cm$. and find the measure of $\angle A$ in degrees

Q. Which of the following method(s) is/are used to construct a right angle without using a protractor?