Converse of the Theorem: Alternate Interior Angles are Equal
Trending Questions
Q.
Question 41
In the given figure, if PQ|| RS and QR || TS, then the value of a is
(a) 95∘
(b) 90∘
(c) 85∘
(d) 75∘
Q.
In the figure given below, if OP || RS, ∠OPQ = 110o and ∠QRS = 130o, then ∠PQR is equal to
60∘
65∘
40∘
45∘
Q. In the given figure, AB = AC, BC = CD and ∠ A = 40∘, find ∠ACD
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1519051/original_6-24.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1519051/original_6-24.png)
- 20∘
- 25∘
- 30∘
- 35∘
Q. ABC is a right triangle right angled at A. D lies on BA produced and DE perpendicular to BC intersecting AC at F. If ∠AFE=130∘, find
(i) ∠BDE (ii) ∠BCA (iii) ∠ABC
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1444220/original_BCL6.png)
(i) ∠BDE (ii) ∠BCA (iii) ∠ABC
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1444220/original_BCL6.png)
Q. In a square PQRS, an equilateral triangle △TQR is formed, then m∠PTS- ?
- 75o
- 90o
- 120o
- 150o
Q.
In the figure given below, if OP || RS, ∠OPQ=110o and ∠QRS=130o, then ∠PQR is equal to
60o
650
450
40o
Q. In the given figure, AE || BD, AC || ED and AB = AC. Find ∠a in degrees.
![194620_435ef6df883c43599c0d84f0fd90d938.png](https://search-static.byjusweb.com/question-images/toppr_invalid/questions/194620_435ef6df883c43599c0d84f0fd90d938.png)
![194620_435ef6df883c43599c0d84f0fd90d938.png](https://search-static.byjusweb.com/question-images/toppr_invalid/questions/194620_435ef6df883c43599c0d84f0fd90d938.png)
Q. Take any point O in the interior of a triangle PQR. Is OR+OP>RP?
Since sum of two sides is greater than third side.
![1645774_8eba2fca67b14b43b479572aa484f9b6.png](https://search-static.byjusweb.com/question-images/toppr_ext/questions/1645774_8eba2fca67b14b43b479572aa484f9b6.png)
Since sum of two sides is greater than third side.
![1645774_8eba2fca67b14b43b479572aa484f9b6.png](https://search-static.byjusweb.com/question-images/toppr_ext/questions/1645774_8eba2fca67b14b43b479572aa484f9b6.png)