Parallelograms
Trending Questions
Q. A quadrilateral with two pairs of opposite sides parallel is a _____.
- triangle
- parallelogram
- parallel lines
- trapezium
Q.
The perimeter of the parallelogram is . If one of the sides is greater than the other by find the lengths of the sides of the parallelogram.
Q. In the following figure ∠ABD = ∠BDC and ∠CBD = ∠ADB. Then, ABCD is a __________.
- triangle
- parallelogram
- pentagon
- hexagon
Q. If ABCD is a parallelogram with AB || CD, AD || BC, and BD is the diagonal, then the △ABD and △BCD are always .
- equilateral
- isoceles
- scalene
- congruent
Q.
ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD.
Show that
Q. In the figure, which pair of angles represent the adjacent angles?
- ∠6 and ∠8
- ∠1 and ∠4
- ∠5 and ∠7
- ∠1 and ∠3
Q. Which of the following statement is/are true in case of a parallelogram?
- Opposite sides are equal
- Diagonals bisect one another
- Diagonals are perpendicular to each other
- Opposite sides are parallel
Q. ABCD is a parallelogram, and BC is twice the length of AB. If the perimeter of ABCD is 360 cm, find the length of AD.
- 60 cm
- 80 cm
- 100 cm
- 120 cm
Q. If in two triangles ABC and PQR , AB = PQ, AC = PR and BC = QR, then .
- ∆ ACB ≅ ∆ PQR
- ∆ ABC ≅ ∆ PQR
- ∆ ABC ≅ ∆ PRQ
Q.
In the figure, there is a jogging track that has to be renovated. The cost of renovation is Rs. 15 per square meters. For the circular parts, the inner and outer radii are 6 m and 8 m respectively. If the total cost of renovation is Rs. 2, 520, find the length of AB.
10 m
15 m
20 m
25 m
Q.
If the sides of △ABC are AB = 5 cm, BC = 4 cm and CA = 3 cm, and sides of △PQR are PQ = 4 cm, QR = 3 cm and RP = 5 cm, then _______.
- △ABC≅△QPR
- △ABC≅△PQR
- △ABC≅△RPQ
- △ABC≅△PRQ
Q. The figure, □ABCD is a parallelogram and its diagonals AC and BD intersect at E.
If l(AB) = 3 cm, l (BC) = 5 cm, m∠BAD = 120° and m∠ADC = 60°, then
(1) l (DC) = ?
(2) l (AD) = ?
(3) m∠BCD = ?
(4) m∠ABC = ?
If l(AB) = 3 cm, l (BC) = 5 cm, m∠BAD = 120° and m∠ADC = 60°, then
(1) l (DC) = ?
(2) l (AD) = ?
(3) m∠BCD = ?
(4) m∠ABC = ?