Permutation under Restriction
Trending Questions
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Find the number of ways in which boys and girls may be seated in a row so that no two girls and no two boys are together.
boys and girls are to be seated in a row such that there are at least boys between the girls. The number of ways this can be done is where
A cake is cut into two equal parts and each part is again cut into two equal halves and it continues in that way. How many times should one cut the cake so that the number of pieces will be 32? [3 MARKS]
The number of digit odd numbers, that can be formed by using the digits when the repetition is allowed, is
- 6C3×4C2
- 4P2×4P3
- 4C2+4P3
- none of these
Write the face value and place value of each odd digit in the given number:
Observe the following pattern and find the missing numbers.
- 216
- 192
- 120
- 72
- 13
- 12
- 14
- 15
- 94
- 49
- 74
- None of these
- 3553
- 4259
- 3753
- 4760
- 11
- 13
- 12
- 15
Column I Column II
(A)The number of permutations containing the word ENDEA is (p)5!
(B)The number of permutations in which the letter # occurs in the first and the last positions is (q) 2×5!
(C)The number of permutations in which none of the lettersD, L, N, occurs in the last five jpositions is (r) 7×5!
(D) The number of pernutations in which the leters A, E, O occur only in odd positions is (s)21×5!
- The number of permutations containing the word ENDEA is (p)5!
- The number of jpermutations in which the letter # occurs in the first and the last positions is (q) 2×5!
- The number of permutations in which none of the lettersD, L, N, occurs in the last five jpositions is (r) 7×5!
- The number of pernutations in which the letersA, E, O occur only in odd positions is (s) 21×5!
Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let m be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue.
Then the value of mn is
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