Conduction Law: Differential Form
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Q.
The temperatures of the two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity K and 2K and thickness x and 4x, respectively, are T2 and T1 (T2>T1). The rate of heat transfer through the slab, in a steady state is (A(T2−T1)Kx)f, with f equal to
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Q.
Find the rate of heat flow through a cross-section of the tapered conical rod shown in figure (Temperature of the big end(θ2)> Temperature of the small end(θ1)), with radius r1 and r2 at the small and big end respectively. Thermal conductivity of the material of the rod is K.