Young's Modulus of Elasticity
Trending Questions
Two steel wires having same length are suspended from a ceiling under the same load. If the ratio of their energy stored per unit volume is , the ratio of their diameters is:
Two wires of the same material and same length but diameters in the ratio are stretched by the same force. The potential energy per unit volume of the two wires will be in the ratio:
A wire fixed at the upper end stretches by length by applying a force . The work done in stretching is:
The diameter of a brass rod is and Youngs modulus of brass is . The force required to stretch it by of its length is
A wire of area of cross section 3.0 mm2and natural length 50 cm is fixed at one end and a mass of 2.1 kg is hung from the other end. Find the elastic potential energy stored in the wire in steady state. Young's modulus of the material of the wire = 1.9×1011Nm−2.Takeg=10ms−2
10-4 J
2 x 10-4 J
3 x 10-4 J
0.5 x 10-4 J
- length of rod
- material of the rod
- rise in temperature
- none of these
- 1:2:3
- 3:2:1
- 5:4:3
- 6:3:4
Two separate wires A and B are stretched by and respectively, when they are subjected to a force of . Assume that both the wires are made up of the same material and the radius of wire B is times that of the radius of wire A. The length of the wires A and B are in the ratio of , Then can be expressed as . What is the value of where ?
A force F doubles the length of wire of cross-section ‘’. What is the Young modulus of wire ?
- 100 N
- 51 N
- 25 N
- none of these
If the force constant of a wire is k, the work done in increasing the length L of the wire by l is
3Kl
2Kl