Activation Energy
Trending Questions
Q.
What is the relation between rate constant and Activation energy?
Q. For a first order reaction, A → P, the temperature (T) dependent rate constant (k) was found to follow the equation:
log k=2000T+6.0
the pre - exponential factor A and the activation energy Eα. respectively, are:
log k=2000T+6.0
the pre - exponential factor A and the activation energy Eα. respectively, are:
- 1.0×106 s−1 and 16.6 kJ mol−1
- 1.0×106 s−1 and 38.3 kJ mol−1
- 1.0×106 s−1 and 9.2 kJ mol−1
- 6.0 s−1 and 16.6 kJ mol−1
Q. Which of the following statements are true?
1. LPG, matchstick, coal, and petrol are the examples of combustible substances.
2. Substances that have a higher ignition temperature than room temperature undergo spontaneous combustion.
3. Burning of kerosene is an example of rapid combustion.
4. Carbon monoxide is produced during complete combustion of coal.
1. LPG, matchstick, coal, and petrol are the examples of combustible substances.
2. Substances that have a higher ignition temperature than room temperature undergo spontaneous combustion.
3. Burning of kerosene is an example of rapid combustion.
4. Carbon monoxide is produced during complete combustion of coal.
- 1 and 3
- 1, 2, and 3
- 2, 3, and 5
- 3 and 4
Q.
The activation energies for the forward and reverse elementary reactions in the system A⇌B are 10.303 and 8.000 k cal respectively at 500K. Assuming the pre-exponential factor to be the same for both the forward and reverse steps and R = 2 cal K−1mol−1, calculate equilibrium constant of the reaction :
10.0
100
0.1
1.00