Mole Concept
Trending Questions
Calculate the molecular mass of:
Ammonium nitrate .
100 g of calcium carbonate on treatment with 73g of hydrochloric acid, produces carbon dioxide. What is the volume of carbon dioxide gas produced when the reaction is taking place at STP?
11.2 l
44.8 l
5.6 l
22.4 l
- True
- False
- 2
- 1
- 0.5
- Cannot be determined
9.033×1023 atoms of hydrogen is equal to:
1.5 gm
0.75 grams
1.5 moles
0.75 moles
Explain fractional atomic mass. What is the fractional mass of chlorine?
How many moles of hydrogen atoms are present in 1 mole of H2O?
4
1
3
2
Define Mole
- 5 moles of H2O
- 12 moles of CO2
- 10 moles of SO2
- 13 moles of NO2
Calculate the molar mass of Sulphur molecule,
Given the atomic masses of S = 32u
- 1440.71 g
- 1248.71 g
- 1448.71 g
- 1438.71 g
(i) 8 g of oxygen atoms
(ii) 4.088×1021 number of oxygen atoms (Atomic mass of O=16 u)
- 1.67×1021H2O molecules
- 1.67×1026H2O molecules
- 1.806×1023H2O molecules
- 1.806×1021H2O molecules
- 6.02×1023
- 19.108×1031
- 6.029.108×1054
- 19.108×6.023×108
- 1.0 gm of oxygen
- 0.5gm of Mg
- 0.5 gm of oxygen
- 1.0 gm of Mg
How will you calculate the number of moles in a substance?
- 1020 molecules
- 10−10 molecules
- 21 molecules
- 1021 molecules.
Find the number of oxygen atoms in 88g of CO2 ?
2.4092×1024
2.4092×1023
2409.2×1024
24.092×1024
112cm3 of a gaseous fluoride of phosphorus has a mass of 0.63 g at STP. Calculate the relative molecular mass of the fluoride. If the molecule of the fluoride contains only one atom of phosphorus, then determine the formula of the phosphorus fluoride (F=19, P=31).
- 0.1 mole, 0.1 mole
- 0.1 mole, 0.2 mole
- 0.5 mole, 0.5 mole
- 0.2 mole, 0.2 mole
- 170.43×10−10g
- 170.43×10−11g
- 340.86×10−11g
- 340.86×10−10g
I 5 moles of CO2 and 5 moles of H2O have the same mass.
II 100 g of NH3 has more atoms than that present in 100 g of N2.
III 16 g of solid sulphur contains 3.76×1022 molecules/
- I and II only
- II and III only
- III only
- I only
Calculate the number of molecules in 1 kg of calcium chloride.
- (6.02×1023)(10.0)(55.9)
- (10.0)×(55.9)×(6.02×1023) atoms
- (10.0)(6.02×1023)(55.9)
- (10.0)(55.9)(6.02×1023)
- (55.9)(10.0)(6.02×1023)