Division of a Polynomial by a Binomial
Trending Questions
Why is division by 0 not defined?
- Quotient = (6x4+5x+9)
Remainder = (10x2+1) - Remainder= (6x2+5x+9)
Quotient= (10x) - Quotient = (6x4+5x+9)
Remainder = (10x) - Quotient = (6x4+5x+9)
Remainder = (x+1)
- Quotient = (a−1+a4)
Remainder = (a2+a−11) - Quotient = (a+51)
Remainder = (a4+a−1) - Quotient = (a−1)
Remainder = (a2+a−1) - Quotient = (a2−1)
Remainder = (2a2+a−1)
In division algorithm when should we stop the division process?
1. When the remainder is zero.
2. When the degree of the remainder is less than the degree of the divisor.
3. When the degree of the quotient is less than the degree of the divisor.
Statement 1, 2 are correct
Statement 2, 3 are correct
Statement 3, 1 are correct
None of these
When we divide 3t4+5t3−7t2+2t+2 by t2+3t+1, we get 3t2−4t+2 as quotient.
True
False
If x2 + y2=14 and xy=3, find the value of 2(x+y)2 − 5(x−y)2.
0
106
14
52
Divide x5−4x3+x2+3x+6 by x3−3x+1, and then find the remainder and quotient.
7,
8,
7,
8,
- 5x4−3x2
- 5x3+3x2
- 5x4+3x2
- 5x3−3x2
- 4b
- 4
- 4b2
- 4b
The degree of the polynomial obtained when 8−6x+x2−7x3+x5 is subtracted from x4−6x3+x2−3x+1 is
5
1
3
4
- Quotient = (6x2+5x+9)
Remainder = (10x) - Quotient = (6+5x+9x)
Remainder = (10x3) - Remainder= (6x2+5x+9)
Quotient = (10x) - Remainder= (6x2+5x+9)
Quotient = (10x2)
- True
- False
(2 marks)
- 4x−25
- 4x−25+85x−57x2+3x−2
- 85x−57x2+3x−2
- 85x−57
- Remainder= 3x2+4x3
Quotient= 12x - Quotient = 3x+4
Remainder = 0 - Remainder= 3x2+4x3
Quotient= 0 - Quotient = 3x2+4x
Remainder = 0
- 3x3−2
- 5x+7x2
- 8
- −6x5+10x3
- True
- False
- 2m2+2m
- 2m3−2m
- 2m2−2m
- 2m3+2m
When we divide 3t4+5t3−7t2+2t+2 by t2+3t+1, we get 3t2−4t+2.
- 3x−2−3x+4x2−1
- 3x−2+3x+43x
- 3x−2+3x+4x2−1
- 3x+4+3x−2x2−1
- x2+x+1
- x2−x−1
- x2+x−1
- x2−x+1
- 5x
- 10
- 10x
- 3x
Divide x3−125 by x2+5x+25 and find the quotient.
x + 5
x - 5
x + 2
If we divide a number by its factor, there can be a remainder left over.
- True
- False
The expression obtained by multiplying (7x−4x2+2x3−5) with (3x−2) is:
6x4−16x3+29x2−x+1
6x4−16x3+27x2−x+10
5x4−16x3+29x2−x+10
6x4−16x3+29x2−29x+10
- x3+2x2+1
- x3−2x2+2
- 3x3+2x2+1
- x3+6x2+1
- x+1
- x+2
- x+3
- x+4