Eqns. reducible to pair of LE in 2 variables
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takes hour more than to walk . But if doubles his pace, he is ahead of by . Find their speed of walking.
2y+53=263−y
14y−8=13
Solve the following pairs of equation
2xyx+y=32, xy2x−y=−310, x+y≠0, 2x−y≠0
Find the values of x and y if :
52+x+1y−4=2
62+x−3y−4=1
Here, x ≠ -2 and y ≠ 4.
x = 1, y = 7
x = -2, y = 2
x = 0, y = 8
x = 7, y = -8
1.6=y1.5
5x−1+1y−2=2
6x−1+3y−2=1
(where x≠1 and y≠2)
- Substitute x=X+1 and y=Y+2
- Substitute 1x−1 as p and 1y−2 as q
- None of the above
- The equation is already linear
2x+3y=13
5x−4y=−2
- x=12, y=13
- x=13, y=12
- x=2, y=3
- x=3, y=2
Is √x=4 linear equation? If not then how the equation can be made linear.
Yes
No, substitute x=u2, now the equation is linear in variable x
No, substitute x=u2, now the equation is linear in variable u
None of these
- 30 km/hr
- 90 km/hr
- 40 km/hr
- 220 km/hr
How will you make the following equation linear?
5x−1 + 1y−2 = 2
6x−1 - 3y−2 = 1
Substitute 1/x-1 as p and 1/y-2 as q
substitute x=x+1 and y=y+2
The equation is already linear
None of the above
- Substitute x=u2, now the equation is linear in variable x
- Substitute x=u3, now the equation is linear in variable u
- Substitute x=u2, now the equation is linear in variable u
- Substitute x=u4, now the equation is linear in variable u
3y+42−6y=−25
1x+3y=1
6x−12y=2
(where x≠0, y≠0)
- x=35, y=73
- x=53, y=152
- x=4, y=9
- x=3, y=11
- 10 km/hr, 30 km/hr
- 10 km/hr, 40 km/hr
- 30 km/hr, 10 km/hr
- 40 km/hr, 10 km/hr
2√x+3√y=2
4√x−9√y=−1
(where x>0, y>0)
- x=9, y=4
- x=4, y=9
- x=3, y=2
- x=12, y=13
5x−1+1y−2=2
6x−1−3y−2=1
(where x≠1, y≠2)
- x=4, y=5
- x=5, y=4
- x=13, y=13
- None of the above
The time taken to travel 30 km upstream and 44 km downstream is 14 hours. If the distance covered in upstream is doubled and distance covered in downstream is increased by 11 km then the total time taken is 11 hours more than earlier. Find the speed of the stream.
4 km/hr
7 km/hr
3 km/hr
6 km/hr