Equation of circle with (h,k) as center
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Q.
The distance between the vertex of the parabola and the centre of the circle is
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Q. Equation of a circle whose centre is origin and radius is equal to the distance between the lines x = 1 and x = -1 is
- x2+y2=4
- x2+y2=1
- x2+y2=−4
- x2+y2=√2
Q. The equation of the circle which passes through the points (2, 3) and (4, 5) and the centre lies on the straight line y - 4x + 3 = 0, is
- x2+y2+4x−10y+25=0
- x2+y2−4x−10y+16=0
- x2+y2−4x−10y+25=0
- x2+y2−14y+8=0
Q. The equation of circle passing through (4, 5) and having the centre at (2, 2), is
- x2+y2+4x+4y−5=0
- x2+y2−4x−4y−5=0
- x2+y2−4x=13
- x2+y2−4x−4y+5=0