Finding Mode for Grouped Data When Class Intervals Are Given
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The modal class of the given data is
ClassFrequency0−52005−1025010−1522515−2030020−25275
15 -20
0-5
5-10
10-15
For the following distribution, the modal class is
MarksNumber of studentsBelow 103Below 2012Below 3027Below 4057Below 5075Below 6080
30-40
50-60
10-20
20-30
The following data shows monthly savings of 100 families . Calculate the mode of the given frequency distribution.
Monthly savings(Rs) Number of families 1000−2000142000−3000153000−4000214000−5000275000−600025
700-800
600-700
900-1000
800 - 900
- 32
- 25
- 35
- 15
- 100
- 50
- 40
- 60
State True or False. The mode of the following data is 133.33.
Class interval100−110110−120120−130130−140140−150Frequency89111210
True
- False
Mode=p+q−f0(q−f0)+(q−f2)×h
- p = l, lower limit of modal class; q=f1, frequency of modal class
- p = l, middle value of modal class; q=f1, frequency of modal class
- p = l, slope; q=f1, frequency of lower class
- p = l, size of class interval; q=f1, frequency of modal class
Which of the following formulae correctly depicts the mode of a modal class?
Cumulative frequency of previous class
Frequency of preceeding class
Frequency of modal class
Frequency of succeding class.
The mode for the given data is ___ .
IQ60−7070−8080−9090−100100−110110−120120−130No. of pupils2351614137
- 98.46
- 96.25
- 95.84
- 95.98
Class interval | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
Frequency | 8 | 10 | ...... | 16 | 12 | 6 | 7 |
- 10
- 15
- 16
- 12
In the fromula for mode of a grouped data ,
mode =l+[t1−t02f1−f0−f2]×h ,
where symbols have their usual meaning f1 represents
Frequency of Modal class
Frequency of the class preceding the modal class
Frequency of the class succeeding the modal class
Frequency of median class
The following data shows monthly savings of 100 families . Calculate the mode of the given frequency distribution.
Monthly savings(Rs) Number of families 1000−2000142000−3000153000−4000214000−5000275000−600025
700-800
600-700
900-1000
800 - 900
- 656200
- 656250
- 655250
- 650250
Lifetimes (in hours) | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 |
Frequency | 10 | 35 | 52 | 61 | 38 | 29 |
- 69.268 hours
- 65.625 hours
- 58.267 hours
- 62.126 hours
Number | 0−3 | 3−6 | 6−9 | 9−12 | 12− | 15−18 | 18−19 | 21− |
Frequency | 4 | 9 | 7 | 6 | 3 | 1 |
- 19
- 31
- 26
- 21
If the preceding and succeeding classes of the modal class have the same frequency, then the mode will be at the midpoint of the modal class.
True
False
Find the mode of the following data. Class interval0−1010−2020−3030−4040−50Frequency71314511
- 20
- 30
- 21
- 25
The following data shows the warranty period of different components. Find the modal warranty period.
Warranty period(years)0−11−22−33−44−55−6Number of components61016251620
- 3
- 3.25
- 3.5
- 4
Find the mode of the following data.
Class interval100−120120−140140−160160−180180−200Frequency10138712
The sum of lower limit and upper limit of modal class is
Warranty period(years)0−11−22−33−44−55−6Number of components61016251620
- Girls
- Equally consistent
- Boys
- Can't be determined