Orthogonality of Two Circles
Trending Questions
Q. If a circle passes through the point (a, b) and cuts the circle x2+y2=p2 orthogonally, then the equation of the locus of its centre is
- x2+y2−3ax−4by+(a2+b2−p2)=0
- 2ax+2by−(a2+b2+p2)=0
- 2ax+2by−(a2−b2+p2)=0
- x2+y2−2ax−3by+(a2−b2−p2)=0
Q.
If two circles which pass through the points (0, a) and (0, -a) cut each other orthogonally and touch the straight line y=mx+c, then
c2=a2(1+m2)
c2=a2(2+m2)
c2=2a2(1+m2)
c2=a2∣∣1+m2∣∣
Q. If A(−2, 3)B(2, −1)C(3, 1) then the locus of P such that PA2+PB2+PC2=7 is a circle with centre
- (2, 1)
- (1, 2)
- (1, 1)
- (2, 2)