The Equations of Motion
Trending Questions
A ball is thrown vertically upwards with a velocity of . Calculate the maximum height to which it rises.
A body is projected vertically up with velocity u. Its velocity at half its maximum height is?
- a=4ms−2, t=30 s
- a=3ms−2, t=30 s
- a=4ms−2, t=40 s
- a=3ms−2, t=40 s
A boy is running along a circular track of radius . He completes one circle in . The average velocity of the boy is
Zero
A baseball is popped straight up into the air and has a hang-time of 6 s. Determine the maximum height to which the ball rises?
180 m
90 m
45 m
22.5 m
A body has an initial velocity of 4 ms−1 and deceleration of 4 ms−2, then what is its final velocity after travelling 2 m?
5 ms−1
- 2 ms−1
4 ms−1
0 ms−1
A person standing on the edge of a cliff of height 40 m above the ground throws the first ball straight up with an initial velocity of 20 ms, and then throws the second ball straight down with the same initial velocity 20 ms. What are their respective velocities just before they hit the ground. (Take a = 10 m/s2)
20√2 m/s, 20√2 m/s
20√2 m/s, 20√3 m/s
20√3 m/s, 20√2 m/s
20√3 m/s, 20√3 m/s
(Take g = 10 ms−2)
- 5 m and 5 ms−1
- 6 m and 6 ms−1
- 7 m and 7 ms−1
- 4 m and 5 ms−1
- Lorry
- Car
- Both will stop at the same distance
- Cannot be said
Brakes are applied to a truck to produce an acceleration of –10m/s2. If the truck takes 5s to stop after applying the brakes, the distance covered by the truck before coming to rest is 250 m.
200 m
125 m
- d≤u2a
- d≤u22a
- d≤u23a
- d≤u24a
A ball thrown up vertically returns to the thrower after 12 seconds. Find the maximum height it reaches.
Match the statements of Column A with those of Column B.
Column A | Column B |
(A) Uniform velocity Derived quantity | (a) |
(B) Average speed | (b) |
(C) Average velocity | (c) Acceleration is zero |
(D) Acceleration | (d) Ratio of total displacement to total time taken |
- 5 cms−1
- 10 cms−1
- 15 cms−1
- 20 cms−1
Average velocity of a particle moving in a straight line, with constant acceleration ‘a’ and initial velocity u in first t seconds is :
u
u + (at/2)
(u + at)/2
u + at
A ball takes t second to fall from a height h1 and 4t seconds to fall from h2. then is
2
4
0.5
0.0625