Brown Ring Test

Q.

The chemical formula of brown ring formed in the brown ring test is .

1. $\left(Fe\right(H_{2}O{)}_{5}NO)S{O}_4$
2. $Fe(NO{)}_{2}S{O}_4$
3. $FeS{O}_4.N{O}_3$

Q.

Why is a fresh solution of ${\mathrm{FeSO}}_4$ used in the test for nitrogen?

Q.

In brown ring test, a freshly prepared ferrous sulphate solution is used because:

1. Ferrous sulphate when exposed to atmosphere oxidizes to ferric sulphate.

2. Ferrous sulphate when exposed to atmosphere reduces to ferric sulphate.

3. Ferric sulphate doesn't give a brown ring.

4. Ferric sulphate will also give a brown ring but will not stay for a longer times.

Q.

Which of the following ions is responsible for the brown colour in the ring test for nitrate?

1. $[\mathrm{Fe}{\left({\mathrm{NO}}_2\right)}_6{]}^{4-}$

2. ${\left[\mathrm{Fe}{\left({\mathrm{H}}_2\right)}_5{\mathrm{NO}}_2\right]}^{+}$

3. ${\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_5{\mathrm{NO}}_2\right]}^{-}$

4. $[\mathrm{Fe}{\left({\mathrm{H}}_2\mathrm{O}\right)}_5\mathrm{NO}{]}^{2+}$

Q.

Choose the correct answer :

(a) The nitrate salt which does not give a mixture of $N{O}_2$ and $O_2$ on heating is :

(i) $AgN{O}_3$, (ii) $KN{O}_3$,

(iii) $Cu(N{O}_3{)}_3$, (iv) $Zn(N{O}_3{)}_2$.

(b) The chemical used in the brown ring test is :

(i) $CuS{O}_4$, (ii) $FeS{O}_4$

(iii) $F{e}_2(S{O}_4{)}_3$ (iv) $ZnS{O}_4$.

(c) Lead nitrate decomposes on heating to give :

(i) NO, (ii) $N_{2}O,$

(iii) $N{O}_2$ (iv) $N_2{O}_5$.

Q. (a) Explain with the help of a balanced equation the brown ring test for nitric acid.
(b) Why is freshly prepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test? [5 MARKS]

Q.

Is NH4Cl soluble in NaOH

Q.

(a) Explain with the help of a balanced equation, the brown ring test for nitric acid.

(b) Why is freshly pepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test ?

Q. Explain with the help of a balanced equation the brown ring test for nitric acid.

Q. Why is freshly prepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test?

Q. Assertion :Both Copper oxide and Manganese dioxide gives reaction with $HCl$. Reason: Only Manganese dioxide gives a gaseous product.

1. Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
2. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
3. Assertion is correct but Reason is incorrect
4. Both Assertion and Reason are incorrect

Q. Why is freshly prepared ferrous sulphate solution used for testing the nitrate radical in the brown ring test?

Q. The chemical formula of brown ring formed in the brown ring test is .

1. $\left(Fe\right(H_{2}O{)}_5\mathrm{NO}){\mathrm{SO}}_4$
2. $\mathrm{Fe}(\mathrm{NO}{)}_2{\mathrm{SO}}_4$
3. ${\mathrm{FeSO}}_4.{\mathrm{NO}}_3$

Q.

The brown ring in the detection of $N{O}_3^{-}$ ion is due to the formation of

1. $N{O}_2$

2. $N_2{O}_3$

3. $N_2{O}_5$

4. $FeS{O}_4.NO$

Q. Which of the following turns a paper, dipped in silver nitrate solution, yellow?

1. Copper carbonate
2. Iodine
3. Nitrogen dioxide
4. Sulphur dioxide

Q.

In brown ring test, which compound is responsible for ring formation?

1. $FeS{O}_4.N{O}_2$

2. None of the above

3. $FeS{O}_4.N_{2}O$

4. $FeS{O}_4.NO$

Q.

Match the following columns

Column 1	Column 2
Brown ring test	$FeS{O}_4.NO$
Brown ring	$N{O}_3^{-}$
Brown ring interfere	$N{O}_2^{-}{l}^{-}$

Q. Which one of the following nitrates will form a metal on strong heating ?

1. Ferric nitrate
2. Copper nitrate
3. Silver nitrate
4. Managanese nitrate