Addition Theorem of Probability for 3 Events
Trending Questions
For the three events A, B and C, P (exactly one of the events A or B occurs) = P(exactly one of the events B or C occurs) = P(exactly one of the events C or A occurs) and P (all the three events occur simultaneously) = , where . Then the probability of at least one of the three events A, B and C occurring is
- 0.8
- 0.9
- 0.25
- 0.5
Suppose that a family has children. Also, suppose that the probability of having a girl is . Find the probabilities that the family has the following children.
Exactly girls and boys
[3]
- 525
- 112
- 14
- None
For the three events A, B and C, P (exactly one of the events A or B occurs) = P(exactly one of the events B or C occurs) = P(exactly one of the events C or A occurs)=p and P(all the three events occur simultaneously)=p2, where 0<p<1/2. Then the probability of at least one of the three events A, B and C occuring is
3p+2p22
p+3p24
p+3p22
3p+2p24
- 1391000
- 77250
- 4812000
- 61500