Application of Mid Point Formula
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ABC is a triangle and G(4, 3) is the centroid of the triangle. If A = (1, 3), B = (4, b) and C = (a, 1). Then the length of side BC is:
10 units
5 units
15 units
25 units
Three vertices of a parallelogram ABCD taken in order are A(3, 6), B (5, 10) and C(3, 2). Then the coordinates of the fourth vertex D is
(1, -2)
(-1, 2)
(2, -1)
(-2, 1)
If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of parallelogram taken in order, find x and y.
(6, 3)
(4, 3)
(2, 5)
(2, 3)
If the vertices of a triangle are (a, 1), (b, 3) and (4, c), then the centroid of the triangle will lie on the x-axis, if
c = -4
b + c = -4
a + c = -4
a + b = -4
If A (1, 2), B (4, y), C (x, 6) and D (3, 5) are vertices of a parallelogram ABCD, find the values of x and y. [4 MARKS]
- 2 sq. units.
- 0.5 sq. units.
- 1 sq. units.
- 1.5 sq. units.
Two vertices of a triangle are (3, –5) and (–7, 4). If its centroid is (2, –1). Find the third vertex.
- (6a+1a+1, 8a+4a+1)
- (6a+2a+1, 8a+4a+1)
- (6+2aa+1, 8+4aa+1)
- (6a+8a+1, 2a+4a+1)
- AC+BA>BC
- AC+BC>AB
- All of these
- AB+BC>AC
If a vertex of a triangle is (1, 1) and the mid-points of the two sides through this vertex are (-1, 2) and (3, 2), then the centroid of the triangle is _____.
(−1, 73)
(−13, 73)
(1, 73)
(13, 73)
Two vertices of a triangle are (3, –5) and (–7, 4). If its centroid is (2, –1). The third vertex is
(2, 10).
(-10, 2).
(2, -10).
(10, -2)
The centroid of the triangle whose vertices are (1, 3) (2, 7) and (12, -16) is
(-5 , 2)
(-5 , -2)
(5 , -2)
(5 , 2)
Two vertices of a triangle are (3, –5) and (–7, 4). If its centroid is (2, –1). Find the third vertex.
(12, -2)
(10, -2)
(9, -2)
(10, -3)
The points A(-a, b), B(-a, c) and C(a, c) form the vertices of a triangle. Which of the following is true?
- Area of the triangle = b(a - c)
- ΔABC is a right angled triangle, right angled at A.
- The triangle is equilateral.
- Area of the triangle = a(c - b)