Converse of Cyclic Quadrilateral Theorem
Trending Questions
What are the properties of a right-angle triangle?
- 80∘
- 70∘
- 60∘
- 90∘
A quadrilateral ABCD is inscribed in a circle such that AB is a diameter and ∠ADC=130∘ . Find ∠BAC.
- 30∘
- 50∘
- 60∘
- 40∘
ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If ∠DBC=70∘, ∠BAC is 30∘, find ∠BCD . Further, if AB = BC, find ∠ECD.
- 2∘
- 3∘
- 50∘
- 4∘
In the given figure, ∠A=70∘ and ∠ABC=50∘ , find ∠DPC and ∠BQC.
30o
40o
20o
50o
\(\text{(D) In the given figure, O is the centre of the arc ABC which subtends an angle of} 130^\circ~ \text{at the centre.}\text{If AB is extended to P then}~\angle PBC =
60∘
130∘
100∘
90∘
Match the two column;
Column-IColumn-II(A) In the given figure, (p)60∘ ABCD is a cyclic Quadrilateral. O is the centre of the circle. If∠BOD=160∘ find the Measure of∠BPD.
(B) In given figure, ABCD is a cyclic(q)65∘ quadrilateral whose side AB is a diameter of the circle through A, B, C, D. If ∠ADC = 130∘, find∠BAC.
(C) In the given figure BD = DC and(r) 40∘ ∠CBD = 30∘ Find m(∠BAC)
(D) In the given figure, O is the centre of the(s) 100∘ arc ABC subtends an angle of 130∘ at the centre. If AB is extended to Pm find∠PBC.
Choose the correct option:
A-s; B-r; C-p; D-q
A-s; B-p; C-q; D-r
A-p; B-q; C-r; D-s
A-s; B-p; C-r; D-q
Find (i) ∠BCD (ii) ∠CAD
If the arms of one angle are respectively parallel to the arms of another angle, then the two angles are :
Neither equal nor supplementary
Not equal but supplementary
Equal but not supplementary
Either equal or supplementary.
i) ∠QAB
ii) ∠PAD
iii) ∠CDB
- 50∘
- 40∘
- 60∘
- 80∘
- 115∘
- 72∘
- 88∘
- 108∘
Prove △TPS∼△TRQ
is a chord of a circle with centre .A is a point on major are .Find the total measure of
If sum of opposite angles of a quadrilateral is 180∘, then the quadrilateral is a _____.
trapezium
cyclic quadrilateral
kite
parallelogram
ABCD is a cyclic quadrilateral. Then which of the angles given add to 180∘?
1
2
- 3
- 4
ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If ∠DBC=80∘ and ∠BAC=40∘, then find ∠BCD.
60∘
80∘
50∘
40∘
- 84∘
- 138∘
- 96∘
- 148∘
(i) ∠BCT
(ii)∠DOC