Distance between two points using Pythagoras theorem
Trending Questions
Q. The points A(0, 6), B(-5, 3) and C(3, 1) are the vertices of a triangle which is
- Scalene
- Equilateral
- None of these
- Isosceles
Q. Assertion: Points A(6, 4), B(-4, -6) and C(4, 6) are such that AB =√200, BC= √208, AC= √8, Since AB+BC>AC, points A, B and C from a triangle.
Reason: If BC2=AB2+AC2, then ΔABC is a right triangle, right angled at A.
Reason: If BC2=AB2+AC2, then ΔABC is a right triangle, right angled at A.
- If both assertion and reason are true but reason is not the correct explanation of assertion.
- If assertion is true but reason is false.
- If assertion is false but reason is true.
- If both assertion and reason are true and reason is te correct explanation of assertion
Q. A right triangle is formed by connecting the 3 coordinates A, B and C as shown in figure. Find the point B if AB and BC are parallel to the coordinate axes.
- (2, 1)
- (3, 2)
- (5, 4)
- (1, 1)
Q.
__
A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches 6 m above the ground. Find the length of the ladder.
Q.
In the given figure, ∠ABC = 90∘ and BM is a median, AB = 8 cm and BC = 6 cm. Then, choose the correct option(s).
MC = 5 cm
AM = 5 cm
MB = 5 cm
AC = 5 cm
Q.
List-II gives distance between pair of points given in List-I, match them correctly.
List−I List II(P)(−5, 7), (−1, 3)(1)5(Q)(5, 6), (1, 3)(2)√8(R)(√3+1, 1), (0, √3)(3)√6(S)(0, 0), (−√3, √3)(4)4√2
P-4, Q-1, R-2, S-3
P-3, Q-2, R-4, S-1
P-1, Q-2, R-3, S-4
P-4, Q-3, R-2, S-1
Q. If the distance between the points (4, p) and (1, 0) is 5, then p=___
- ±4
- ±2
- ±2√2
- ±4√2
Q. The distance of point P(x, y) from the origin is =√x2+y2
- True
- False
Q.
The length of the hypotenuse in the figure is:
6
5
4
3
Q.
The distance between the points (a cos25∘, 0) and (0, a cos65∘) is
acos35∘
a
0.5a
2√a