Feasible Solution
Trending Questions
Q.
Assume that the below situation can be expressed as a linear cost function. Find the cost function in each case: Fixed cost:; items cost to produce.
Q. The optimal solutions for 'investment and profit' based question, the ratio of profit to the investment is minimum.
- False
- True
Q.
Which of the following are feasible solutions for a linear programming problem with constraints
x ≥0, y ≥ 0
3x+5y ≤ 15
5x+2y ≤ 10
(1, -1)
(-3, 5)
(0, 0)
- (2, 0)
Q. A manufacturing company makes two models A and B of a product. Each piece of Model A requires 9 labour hours for fabricating and 1 labour hour for finishing. Each piece of Model B requires 12 labour hours for fabricating and 3 labour hours for finishing. For fabricating and finishing, the maximum labour hours available are 180 and 30 respectively. The company makes a profit of Rs 9000 on each piece of model A and Rs 11000 on each piece of Model B.How many pieces of Model A and Model B should be manufactured per week to realise a maximum profit?
- 20 pieces of model A & 0 pieces of model B
- 0 pieces of model A & 10 pieces of model B
- 12 pieces of model A & 6 pieces of model B
- 10 pieces of model A & 10 pieces of model B
Q. Determine graphically the minimum value of the objective function
Z = 50x + 20y
subject to the constraints:
2x – y ≥ – 3
3x + y ≥ 3
2x – 3y ≤ 12
x ≥ 0, y ≥ 0
Z = 50x + 20y
subject to the constraints:
2x – y ≥ – 3
3x + y ≥ 3
2x – 3y ≤ 12
x ≥ 0, y ≥ 0
- 50
- 60
- 100
- 300
Q. Solve the following linear programming problem graphically:
Minimise Z = 50x + 25y
subject to the constraints:
x + 2y ≥ 10
3x + 4y ≤ 24
x ≥ 0, y ≥ 0
Minimise Z = 50x + 25y
subject to the constraints:
x + 2y ≥ 10
3x + 4y ≤ 24
x ≥ 0, y ≥ 0
- 125
- 150
- 275
- 400
Q. The feasible region for an LPP is shown in the Figure.
Let F = 3x – 4y be the objective function. Maximum value of F is.
Let F = 3x – 4y be the objective function. Maximum value of F is.
- 0
- 8
- 6
- -12
Q. The corner points of the feasible region determined by the system of linear constraints are (0, 0), (0, 40), (20, 40), (60, 40), (60, 0). The objective function is
Z = 4x + 3y.
Compare the quantity in Column A and Column B
Column A Column B
Maximum of Z 325
Z = 4x + 3y.
Compare the quantity in Column A and Column B
Column A Column B
Maximum of Z 325
- The quantity in column A is greater
- The quantity in column B is greater
- The two quantities are equal
- The relationship can not be determined on the basis of the information
supplied